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3 years ago

The heights of 200 adults were recorded and divided into two categories.

Mathematics

2 answers:

gayaneshka [121]3 years ago

8 0

The Answer is A

Hope this helps

Vlad [161]3 years ago

3 0

Answer: the answer is B

Step-by-step explanation:

14+6 is 16. Add 88 to 16 and you get 104. 200-104=96.

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Find the area of a square with side length 13 ft

Strike441 [17]

The area of a square is the length of the side squared. 13^2 = 169
The area of a square with a side length of 13 feet is 169 feet.

Hope this helps =)

8 0

3 years ago

A circle is translated 4 units to the right and then reflected over the x-axis. Complete the statement so that it will always be

Natali [406]

Options

The circle at the new location has _____________ the original circle.

- the same center as

- twice the circumference of

- half the radius of

- the same area as

Answer:

the same area as

Step-by-step explanation:

When a circle is translated and reflected, the center of the circle will change; however, its area, circumference, radius and diameter remain the same.

This is so because, translation and reflection only affect the positioning of the circle not the size.

Considering the above analysis, we can conclude that option d answers the question correctly.

8 0

3 years ago

Consider a tank used in certain hydrodynamic experiments. After one experiment the tank contains liters of a dye solution with a

Alja [10]

Answer:

t = 460.52 min

Step-by-step explanation:

Here is the complete question

Consider a tank used in certain hydrodynamic experiments. After one experiment the tank contains 200 liters of a dye solution with a concentration of 1 g/liter. To prepare for the next experiment, the tank is to be rinsed with fresh water flowing in at a rate of 2 liters/min, the well-stirred solution flowing out at the same rate.Find the time that will elapse before the concentration of dye in the tank reaches 1% of its original value.

Solution

Let Q(t) represent the amount of dye at any time t. Q' represent the net rate of change of amount of dye in the tank. Q' = inflow - outflow.

inflow = 0 (since the incoming water contains no dye)

outflow = concentration × rate of water inflow

Concentration = Quantity/volume = Q/200

outflow = concentration × rate of water inflow = Q/200 g/liter × 2 liters/min = Q/100 g/min.

So, Q' = inflow - outflow = 0 - Q/100

Q' = -Q/100 This is our differential equation. We solve it as follows

Q'/Q = -1/100

∫Q'/Q = ∫-1/100

㏑Q = -t/100 + c

$Q(t) = e^{(-t/100 + c)} = e^{(-t/100)}e^{c} = Ae^{(-t/100)}\\Q(t) = Ae^{(-t/100)}$

when t = 0, Q = 200 L × 1 g/L = 200 g

$Q(0) = 200 = Ae^{(-0/100)} = Ae^{(0)} = A\\A = 200.\\So, Q(t) = 200e^{(-t/100)}$

We are to find t when Q = 1% of its original value. 1% of 200 g = 0.01 × 200 = 2

$2 = 200e^{(-t/100)}\\\frac{2}{200} = e^{(-t/100)}$

㏑0.01 = -t/100

t = -100㏑0.01

t = 460.52 min

6 0

3 years ago

14.3p – 32.24 = 127.92 14.3p – 32.24 + 32.24 = 127.92 + 32.24 14.3p = 160.16 StartFraction 14.3 p Over 14.3 EndFraction equals S

DiKsa [7]

Answer:

p = 11.2

Step-by-step explanation:

The computation is shown below:

Data provided in the question

2.6(5.5p – 12.4) = 127.92

Now

Distributive Propertyis

14.3p - 32.24 = 127.92

Addition Property is

14.3p = 127.92 + 32.24

Division Property is

14.3p ÷ 14.3 = 160.16 ÷ 14.3

p = 11.2

We simply find the value of p by applying the distributive property, addition property, and the division property and the same is to be considered

8 0

3 years ago

Cheryl has $100 on her subway gift card. Each week she buys the same lunch for $10. She wants to continue using the card until t

ziro4ka [17]

Answer:

100-60=40

Step-by-step explanation:

5 0

3 years ago

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