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Masteriza [31]
3 years ago
10

Which answers show a correct plan to solve this problem?

Mathematics
1 answer:
uranmaximum [27]3 years ago
3 0
A. & B. Is the correct answer.

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Why does (x-2)^2+9=0 have no real solutions?
alex41 [277]

Answer:

see explanation

Step-by-step explanation:

Given

(x - 2)² + 9 = 0 ( subtract 9 from both sides )

(x - 2)² = - 9  ( take the square root of both sides )

x - 2 = ± \sqrt{-9}

\sqrt{-9} yields no real solutions

There is no real number when multiplied by itself gives - 9

In fact the solutions to \sqrt{-9} are said to be imaginary, that is ± 3i

where i = \sqrt{-1}

If interested investigate further.

7 0
3 years ago
Determine the possible side lengths of the third side of a triangle with known side lengths 3 and 6. answers: –3 < c < –9
vovangra [49]

Answer:

3 < c < 9

Step-by-step explanation:

The length of a side of a triangle cannot be negative. This eliminates the first and last options.

The addition of two sides of a triangle must be greater than the third side. In this case:

3 + 6 = 9 > c

So, the second option is correct. The third option is not correct, because, for example, c = 8 is possible

4 0
3 years ago
What is the value of x in simplest radical form?
Vikki [24]

Answer:

It's 90 because we'll make it equal

5 0
3 years ago
Find f(–2) for the function f(x) = 3x2 – 2x + 7.
sattari [20]

Answer:

23

Step-by-step explanation:

3(-2)2-2(-2)+7

3(4)-(-4)+7

12+4+7

8 0
3 years ago
Select all that could be x
kari74 [83]

Answer:

4 (a.)

Step-by-step explanation:

The x line has to be under 7 and 6 is too close to 7, therefore 4 is the answer

8 0
4 years ago
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