Ok, so user says that it should be solve for vertex not vertex form
(x,y)
to find the vertex of
y=ax^2+bx+c
the x value of the vertex is -b/2a
the y value is found by plugging in the x value for the vertex back into the original equation and evaluating
y=-2x^2-12x-28
a=-2
b=-12
xvalue of vertex is -(-12)/(2*-2)=12/-4=-3
x value of vertex is -3
plug backin for x
y=-2x^2-12x-28
y=-2(-3)^2-12(-3)-28
y=-2(9)+36-28
y=-18+8
y=-10
yvalue is -10
x value is -3
vertex is (-3,-10)
Answer:
The answer is C. 8 mm
Step-by-step explanation:
For me, i was able to divide the 80 by 12 and get 6.667 thus i was able to round up and conclude the answer in the answer choices
Answer:
12 sorry if its wrong
Step-by-step explanation:
This problem involves the dot product.
You must provide all info for position vector m. Your (2,) is inadequate.
Supposing that the terminal point of vector m were (2,3), then
m dot n would equal 8, or 8 = 2*2+3*y. Then 8 = 4 + 3y, and 4 = 3y, and y =3/4.
Please type in the terminal point of vector m and then answer this question following the above example.
