4 hundreds, 2 tens, 1 ones
Hello from MrBillDoesMath!
Answer: 6 u^2 + 4u + 6 = 0 where u = (x-5)^2
Discussion; I think the problem statement should actually be to rewrite <u>this</u> equation:
6 (x-5)^4 + 4 (x-5)^2 + 6 -= 0.
Note the power of "x-5" is 4 in the first term and is 2 in the second term. That is, the power of x-5 in the first terms is double, or the square, of the (x-5) power occurring in the second term. This suggest the substitution u = (x-5)^2. Then the equation can be rewritten as
6 u^2 + 4u + 6 = 0
which is a quadratic in "u".
Regards, MrB
1130
600 = 8(75) + 0
75 = 8(9) + 3
9 = 8(1) + 1
1 = 8(0) + 1
Write the remainder in reverse order,
1130
that's the answer
Mark brainliest please
Answer:
b. 40
Step-by-step explanation:
The value of x (exterior angle) is equal to half of the difference of given arcs
(100 - 20) ÷ 2 = 40