If you have a graphing calculator (such as a TI-84), you can use the normalcdf feature by clicking on the blue "2nd" button, then the "vars" button and then choice 2. Since you are finding the proportion of hybrids that get over 61 mpg, the lower bound is 61, the upper bound is infinity (you can type in 99999), the mean is 57, and the standard deviation is 3.5. So... normalcdf(61,99999,57,3.5) = .1265. This means that 12.65% of the hybrids get over 61 mpg.
Answer:
atq= let no.be x and y
x= 4y-3.......(1)
x-2y=7....(2)
subtracting both eqn
x-x+2y=4y-3-7
2y=4y-10
-2y= -10
y=5 ........second no.
first no...x=7+2y=7+10=17.......first no....
4/7m = 2/7(2m + 1)
4/7m = 4/7m + 2/7
4/7m - 4/7m = 2/7
0 = 2/7 (incorrect)
no solution
Answer:
12
Step-by-step explanation:
since the function is -2x+8 and you have been told to find f(-1.8) you have to replace -1.8 were there's x in the function.
f(x)=-2x+8
f(-1.8)=-2x+8
=-2(-1.8)+8
=3.6+8
=11.6 round off to 12
I hope this helps
