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3 years ago

What happens to the area of a circle when the radius is tripled

2 answers:

8 0

<span>A = pi*r^2
ATriple = pi*(3r)^2 = 9*pi*r^2 = 9 A

Triple the radius, increase the area by a factor of 9.</span><span>

i hope this has helped!</span>

iris [78.8K]3 years ago

7 0

The area is multiplied by 9 (I'm pretty sure)

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Solve for V please!!!!!!!

enyata [817]

Answer:

v = 126°

Step-by-step explanation:

Since 54° and u are corresponding angles in parallel lines, they are equal, hence, u = 54°. u and v are Same Side Interior angles. In parallel lines, Same Side Interior angles are supplementary (meaning that they add up to 180°), therefore, v = 180 - u = 180 - 54 = 126°.

6 0

3 years ago

23. Eduardo wants to get a grade of 95 in his math

dem82 [27]

Answer:

105

Step-by-step explanation:

It is easy to calculate: add up all the numbers, then divide by how many numbers there are. In other words it is the sum divided by the count.

(91+89+X)/3 =95

91+89+X =95*3

180+X =285

X =285 - 180

=105

7 0

3 years ago

35/8 as a mixed number

Lesechka [4]

You would divide 8 into 35 which would give you 4. 8×4=32 ,then you'd have a remaining of 3 left over so you would put that where the numerator is and 4 becomes your whole number. The denominator stays the same.
35 ÷ 8 = 4 3/8

4 0

3 years ago

Read 2 more answers

Determine mu Subscript x overbar and sigma Subscript x overbar from the given parameters of the population and sample size. mu e

Mademuasel [1]

Answer:

$\bar x \sim N(\mu_{\bar x}=86, \sigma_{\bar x}=3)$

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The central limit theorem states that "if we have a population with mean μ and standard deviation σ and take sufficiently large random samples from the population with replacement, then the distribution of the sample means will be approximately normally distributed. This will hold true regardless of whether the source population is normal or skewed, provided the sample size is sufficiently large".

Solution to the problem

Let X the random variable who represents the variable of interest. We know from the problem that the distribution for the random variable X is given by:

$X\sim N(\mu =86,\sigma =24)$

We select a sample of size n=64. That represent the sample size.

From the central limit theorem we know that the distribution for the sample mean $\bar X$ is given by:

$\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})$

The mean for the sample distirbution would be given by:

$\mu_{\bar x}=86$

And the deviation given by:

$\sigma_{\bar x} =\frac{24}{\sqrt{64}}=3$

And then the distribution for the sample mean is:

$\bar x \sim N(\mu_{\bar x}=86, \sigma_{\bar x}=3)$

7 0

3 years ago

Logx + log(3x-13) = 1

Tom [10]

X = 5
Condense the left side.
log x(3x-13)=1
Put a base 10 on each side to clear the log.
x(3x-13)=10
3x^2-13x-10=0
Factoring you get x=5 and x=-2/3. The domain for log is x>0 so the -2/3 is an extraneous solution.

8 0

3 years ago