Determine whether each equation is a linear equation. ... –2x – 3 = y .... linear. 16. 4y. 2. + 9 = –4. SOLUTION: Since y is squared, the equationcannot be written in standard form.
There actually isn't anything to 'work'. There's no question there.
The function simply describes the relationship between two numbers.
It says that whatever you pick for the first number, the second number is
(-4 times the square of the first one) plus (7 times the first one) plus (6) .
Your teacher may have assigned you something to do with the function,
like draw the graph of it, or find its maximum value (2.9375), or find where
it crosses the x-axis (2.381 and -0.63) or the y-axis (6).
But we can't tell what you've been assigned to do with it. The function alone,
just as you've posted it, isn't asking a question, and doesn't call for any work.
Your answer would be 91.1 units².
We can split this shape into a trapezium and a semicircle, and then find the area of both and add them.
To find the area of a trapezium, the formula is
(a + b)/2 × h, which means we do 14 (the length of AD) + 8 (the length of BC) = 22, and 22/2 = 11. Then we multiply 11 by the height of the trapezium, which is 6 because 10 - 4 = 6. This gives us the area of the trapezium as 66 units².
To find the area of a semicircle, the formula is πr²/2, and the radius is 4 because the diameter is 8 (16 - 8 = 8). This means we do π4²/2 = 16π\2 = 8π = 25.13.
Then we need to add together 66 and 25.13, which equals 91.13, or 91.1 to the nearest tenth.
I hope this helps!
Answer:
The length of rectangle is 
The width of rectangle is 
Step-by-step explanation:
Let
x-----> the length of rectangle
y----> the width of rectangle
we know that
The area of rectangle is equal to
so
-----> equation A
-----> equation B
substitute equation B in equation A and solve for y
using a graphing calculator
The solution is
Find the value of x
-----> 
