White matter is made of axons connecting different parts of grey matter to each other
Answer:
For evaporation you need a warm, preferably humid temperature. The rate of evaporation increases with an increase in temperature. A windy climate is best, as wind helps to remove the evaporated water vapour, and therefore creating a better scope for evaporation to continue. The speed of wind is important for evaporation because the wind pulls in dry air, increasing the rate of evaporation.
Short Answer- Hot and humid temperature, lots of wind speed.
₈O¹⁸ + ₁¹H(proton) ⇒ ₉F¹⁸ + ₀n¹(neutron) + ₀γ⁰
(gamma)
<h3>Further explanation</h3>
Given
Fluorine-18
Oxygen-18
Required
Nuclear equation
Solution
Radioactivity is the process of unstable isotopes to stable isotopes by decay, by emitting certain particles,
- alpha α particles ₂He⁴
- beta β ₋₁e⁰ particles
- gamma particles ₀γ⁰
- positron particles ₁e⁰
- neutron ₀n¹
The principle used is the sum of the atomic number and mass number before and after the decay reaction is the same
The reaction
₈O¹⁸ + ₁¹H(proton) ⇒ ₉F¹⁸ + ₀n¹(neutron) + ₀γ⁰
(gamma)
The chemical symbol for sodium bicarbonate is NaHCO₃. Its molar mass is calculated by adding the product of the molar mass of each of the component and the number of moles. That is,
molar mass of NaHCO₃ = (1 mol Na)(23 g Na/1 mol Na) + (1 mol H)(1 g H/ 1 mol H) + (1 mol C)(12 g C/1 mol C) + (3 mol O)(16 g O/1 mol O)
molar mass of NaHCO₃ = 84 g/mol
Same is to be done with sodium carbonate which has a molar mass of Na₂CO₃
molar mass of Na₂CO₃ = (2 mol Na)(23 g Na/1 mol Na) + (1 mol C)(12 g C/1 mol C) + (3 mol O)(16 g O/1 mol O)
molar mass of Na₂CO₃ = 106 g/mol
The decomposition of sodium bicarbonate to sodium carbonate is shwon below,
2NaHCO₃ --> Na₂CO₃ + H₂O + CO₂
Through conversion factors and dimensional analysis,
(1.678 g NaHCO₃)(1 mol NaHCO₃/84 g NaHCO₃)(1 mol Na₂CO₃/2 mol NaHCO₃)(106 g NaHCO₃/1 mol NaHCO₃)
= 1.06 g Na₂CO₃
<em>ANSWER: 1.06 g Na₂CO₃</em>
Yes, the formation of 1 mol of NH3 from H2 and N2 differ from Q for the formation of NH3 from H2 and 1mol of N2
Solution:
Equation for the formation of 1 mol of NH3
3/2H2(g)+ 1/2N2(g) → NH3(g)
The Q of this reaction is
Q1 = [product] / [reactant]
Q1 = [NH 3 ] / [H2]^3/2 [N2]^1/2
Equation for the formation of NO3 from 1 mol of N2
3H 2 (g) + N2(g) → 2NH 3(g)
The Q of this reaction
Q 2 = [product] / [reactant]
Q 2 = [NH 3 ]^2 / [H 2 ]^3 [N 2 ]
The relationship between the two Q's is
(Q1)^2 = Q2
To learn more about the Q click the given link
brainly.com/question/12693045
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