Let 
be the cat's speed just as it leaves the edge of the table. Then taking the point 1.3 m below the edge of the table to be the origin, the cat's horizontal position at time 
is given by
and its height is
where 
is 9.8 m/s^2, the magnitude of the acceleration due to gravity.
The time it takes for the cat to hit the ground is with
(Unfortunately, this doesn't match any of the given options...)
The cat lands 0.75 m away (horizontally) from the edge of the table, so that its speed was
(Again, not one of the answer choices...)
I'm guessing there's either a typo in the question or answers.
The required range of the data is 24mm
The range of data is the difference between the largest value and the least value in a set of data.
Since we are not given the range of data. Let's assume we gave the following data:
34mm, 30mm, 20mm, 44mm, 31mm
From the data
Highest measurement = 44mm
Least measurement = 20mm
Find the range
Range = Highest measurement - Least measurement
Range = 44mm - 20mm
Range = 24mm
Hence the required range of data is 24mm
<em>NB: The concept can be applied to any set of data given for other measurements in (b) and (c)</em>
<em>Learn more here: brainly.com/question/1786006</em>
<span>Simplifying
2x + n = 3
Reorder the terms:
n + 2x = 3
Solving
n + 2x = 3
Solving for variable 'n'.
Move all terms containing n to the left, all other terms to the right.
Add '-2x' to each side of the equation.
n + 2x + -2x = 3 + -2x
Combine like terms: 2x + -2x = 0
n + 0 = 3 + -2x
n = 3 + -2x
Simplifying
n = 3 + -2x</span>
Answer:
4x-3y+12=0 is required eqn
Step-by-step explanation:
Let, 3,8 be x1,y1
9,16 be x2,y2
Now,
Eqn of st.line is y-y1 = y2-y2/x2-x1 * (x-x1)
y-8 = 16-8/9-3 * (x-3)
y-8 = 4/3*(x-3)
3y-24 = 4x-12
4x-3y+12=0 is required eqn
Answer:
-5.2
Step-by-step explanation:
-8+1.5 = -6.5
-6.5 * 4/5 = -6.5 * 0.8 = -5.2
