Given that sin0=21/29 what is the value cos 0 for 0°< 0<90°
1 answer:
Answer:
20/29
Step-by-step explanation:
sin θ = 21/29
Use Pythagorean identity:
sin² θ + cos² θ = 1
(21/29)² + cos² θ = 1
441/841 + cos² θ = 1
cos² θ = 400/841
cos θ = ±20/29
Since 0° < θ < 90°, cos θ > 0. So cos θ = 20/29.
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