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Nina [5.8K]
3 years ago
13

How to do the problem and what the answer is this thing is due today(30 points!)

Mathematics
1 answer:
Murrr4er [49]3 years ago
8 0

Answer:

40°

Step-by-step explanation:

complementary angels makes the sum of two angles = 90°

so

<ABC + < CBD = 90°

if <ABC = 50°

then 90° - 50° = 40°

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Add 4/5 + 1/4 visually!
Greeley [361]

Answer:

1 and 1/20

Step-by-step explanation:

LCM of 5 and 4 = 20

4/5 = 16/20

1/4 = 5/20

6 0
3 years ago
Suppose a shipment of 120 electronic components contains 3 defective components. to determine whether the shipment should be​ ac
Likurg_2 [28]

For this problem, the most accurate is to use combinations


Because the order in which it was selected in the components does not matter to us, we use combinations

Then the combinations are nC_r = \frac{ n! }{r! (n-r)!}

n represents the amount of things you can choose and choose r from them


You need the probability that the 3 selected components at least one are defective.

That is the same as:

(1 - probability that no component of the selection is defective).

The probability that none of the 3 selected components are defective is:

P = \frac{_{117}C_3}{_{120}C_3}


Where _{117}C_3 is the number of ways to select 3 non-defective components from 117 non-defective components and _{120}C_3 is the number of ways to select 3 components from 120.

_{117}C_3 = 260130

_{120}C_3 = 280840


So:

P = \frac{260130}{280840} = 0.927


Finally, the probability that at least one of the selected components is defective is:


P = 1-0.927 = 0.0737

  P = 7.4%

3 0
3 years ago
Is 6 over 2 equivalent to 3
kaheart [24]
Yes, 6 over 2 equals to 3.

6 = 2 x 3

6/2 = (2 x 3)/2 = 3
5 0
3 years ago
una fotografía se reduce a una escala de 1:3 y enseguida se reduce nuevamente con una escala de 1:4 ¿cuáles la reduccion total q
Scrat [10]

Answer:

I don't speak that language

8 0
3 years ago
Uhmmm helppppppp pls lol​
natulia [17]

Answer:

h=81

Step-by-step explanation:

Dont know how to explain but this is the answer

7 0
3 years ago
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