Given input 3823, 8806, 8783, 2850, 3593, 8479, 1941, 4290, 8818, 7413, and a hash function h(x = x mod 13, show the resulting s
eparate chaining table.
1 answer:
Hello:
<span> 3823=13(294)+1
, 8806=</span>13(677)+5<span>
8783=</span>13(675)+8<span>
2850=</span>13(219)+3<span>
3593=</span>13(276)+5<span>
8479=</span>13(652)+3<span>
1941=</span>13(149)+4
4290=13(330)
8818=13(678)+4
7413=13(570)+3
<span>3823=1 mod 13
</span><span>8806 = 5mod 13
</span> 8783<span>= 8 mod 13 ........continue
</span>
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