Number of lawn mowing = x.
His cost per lawn for fertilizer = $6.
His cost per lawn for labor = $14.
Total cost per lawn for fertilizer and per lawn for labor for him = 6+14 = $20.
He charges = $25 per lawn.
So, profit per lawn = 25 - 20 = $5.
Therefore, for mowing x number lawn could be represented by polynomial that represents his weekly profit.
<h3>a) P(x) = 5x.</h3>
b) For mowing 40 lawns per week total profit would be
P(40) = 5(40) = $200.
c) Number of weeks an year = 52.
Therefore,
<h3>Annual profit is 52 * 200 = $10400.</h3>