Answer:
Step-by-step explanation:
He bought a total of 5 tickets, some child, some adult. This is the NUMBER equation.
# of adult tickets + # of child tickets = 5 tickets
Now for the COST equation. Each child ticket costs $2, so the expression for that is 2c; each adult ticket costs $8, so the expression for that is 8a. He spend a total of $22:
$2c + $8a = $22
Money and the number of tickets are NOT THE SAME so they cannot be put into the same equation. They won't add or subtract because they're not like.
Your system is choice A
The formula for perimeter is P = 2length + 2width (P = 2L + 2W)
You know that the length is 4 more yards then twice the width. In equation form this would be:
length = 4 + 2w
Plug what you know into the perimeter formula:
26 = 2(4 + 2w) + 2w
First you must distribute the 2 to the numbers inside the parentheses, which would be 4 and 2w...
26 = (2 * 4) + (2 * 2w) + 2w
26 = 8 + 4w + 2w
Now you must combine like terms. This means that first numbers with the same variables (w) must be combined...
26 = 8 + 4w + 2w
4w + 2w = 6w
26 = 8 + 6w
Now bring 8 to the left side by subtracting 8 to both sides (what you do on one side you must do to the other). Since 8 is being added on the right side, subtraction (the opposite of addition) will cancel it out (make it zero) from the right side and bring it over to the left side.
26 - 8 = 8 - 8 + 6w
18 = 0 + 6w
18 = 6w
To isolate w divide 6 to both sides
18 / 6 = 6w / 6
w = 3
We know that the width is 3 ft
Now you must find the length. To do this plug 3 where you see w in the equation:
length = 4 + 2w
l = 4 + 2(3)
l = 4 + 6
l = 10
We know that length is 10 ft
Letter B. is the correct answer
Hope this helped!
~Just a girl in love with Shawn Mendes
Add the equations,just the way they appear there.
-- Add the top 'x' to the bottom 'x'. Write the sum under the 'x's.
-- Add the '+y' and the '-y'. Write the sum under the 'y's.
-- Add the '2' and the '4'. Write the sum under them, with n " = " sign
before it.
You should now have an equation with only 'x' in it and no 'y'.
You can easily solve that one and find out the value of 'x'.
Once you know the value of 'x', go back to either one of the original
equations, and plug the number-value of 'x' in place of 'x'.
You'll then have an equation with only 'y' in it and no 'x'.
You can easily solve that one and find out the value of 'y'.
3x = 2x + 20
3x - 2x = 20
x = 20