The 2.5% of people who slept the most got more sleep than how many hours of sleep
1 answer:
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The question is incomplete, here is the complete question:
The half-life of a certain radioactive substance is 46 days. There are 12.6 g present initially.
When will there be less than 1 g remaining?
<u>Answer:</u> The time required for a radioactive substance to remain less than 1 gram is 168.27 days.
<u>Step-by-step explanation:</u>
All radioactive decay processes follow first order reaction.
To calculate the rate constant by given half life of the reaction, we use the equation:
where,
= half life period of the reaction = 46 days
k = rate constant = ?
Putting values in above equation, we get:
The formula used to calculate the time period for a first order reaction follows:
where,
k = rate constant =
t = time period = ? days
a = initial concentration of the reactant = 12.6 g
a - x = concentration of reactant left after time 't' = 1 g
Putting values in above equation, we get:
Hence, the time required for a radioactive substance to remain less than 1 gram is 168.27 days.
Answer: 0.01429
Step-by-step explanation:
1.429 x
Now is just 1/100 or 0.01, because 10^2 is 100
Now we can multiply 1.429 by 0.01 which is 1.429 x 0.01
Or the easy way, we can just place the decimal two places to the left because the power is -2, so 2 places to the left. Moving the decimal to the left makes the number smaller.
So, take 1.492 and move its decimal 2 places to the left
We get 0.01429