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Sunny_sXe [5.5K]
3 years ago
6

Please help and answer correctly

Mathematics
1 answer:
astra-53 [7]3 years ago
5 0
Set the equations equal to each other. Then, subtract 10x from 10x and 10x from 13x. You now have -25=3x-55. Add 55 to both sides. You now have 30=3x. Divide 3 from both sides. X equals 10. Now find y. Take one of the equations and substitute x in. Do y=10(10)-25. Your y is 75.
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Write the equation of a line that is parallel to 4x-2y=3 and is passing through the point (2,1)
Temka [501]

Answer:

y= 2x -3

Step-by-step explanation:

Let's rewrite the given equation into the form of y=mx+c, so that we can find the gradient of the line. In this form, m (coefficient of x) is the gradient.

4x -2y= 3

2y= 4x -3

<em>Divide</em><em> </em><em>by</em><em> </em><em>2</em><em> </em><em>throughout</em><em>:</em>

y = 2x - 1 \frac{1}{2}

Thus the gradient is 2.

Parallel lines have the same gradient thus the line would also have a gradient of 2.

Substitute m=2 into the equation:

y= 2x +c

To find the value of c, substitute a pair of coordinates.

When x=2, y=1,

1= 2(2) +c

1= 4 +c

c= 1 -4

c= -3

Thus, the equation of the line is y= 2x -3.

5 0
3 years ago
HELP PICTURE SHOWN!!!!
laila [671]
I hate APEX!

A is right since the graph would start at 2 and go towards negative infinity

D is right both graphs approach +2 as thier highest values
6 0
3 years ago
Please someone answer these 2 questions
saveliy_v [14]
1. C
2.A
Hope this helps, good luck :D
4 0
3 years ago
Calcula el área de un rombo cuya diagonal mayor mide 10 cm y cuya diagonal menor es la mitad de la mayor.
attashe74 [19]

Respuesta:

25 cm²

Explicación paso a paso:

El área A de un rombo tiene:

A = pq / 2

Donde pyq son las diagonales

Tomando p como la diagonal más grande = 10 cm

Diagonal más pequeña, q = 1/2 * 10 = 5cm

Por lo tanto, el área del rombo es:

A = (10 * 5) / 2

A = 50/2

A = 25 cm²

5 0
3 years ago
WILL GIVE BRAINLIEST + 5 STAR<br><br> x=<br> Length=<br> Width=
jarptica [38.1K]

Answer:

16

14

8

Step-by-step explanation:

6 0
3 years ago
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