Answer:
<h3>
(base)² + (altitude)² = (hypotenuse) ²</h3>
Therefore,
2²+5² = c² will be matched.
Answer:
y=3x+5
Step-by-step explanation:
- start by putting 18x on the other side of the equation
- to do this you have to subtract, so it will be -18x now
2. now you have -6y=-18x-30
3. now you need to divide -6 by -18 and -30 on the other side to get y by itself
4. this will leave you with y=3x+5 because 6 divided by 18 is three and 30 divided by 6 is five.
I hope this helps!!
The distance travelled by an object at time t is given by: d = stwhere d is the distance, s is the speed and t is the time.
Given that the cheetah travels a maximum of 70mph, the distance travelled by the cheetah travelling at 70mph at time t is given by d = 70t
There are 60 mins in one hour, so the distance given in miles per minutes is d = 70/60t = 1.167 miles per minutes.
Part B:
Given that t = 10 minutes, the distance covered by the cheetah in 10 minutes is d = 1.167 x 10 = 11.67 miles.
Part C:
If the cheetah sprinted at maximum speed for 8 minutes and then slowed to 40 mph for the next 8 minutes, then the number of minutes the cheetah have traveled in the first 8 minutes is given by
d = 1.167 x 8 = 9.33 miles.
Part D:
If the cheetah sprinted at maximum speed for 8 minutes and then slowed to 40 mph for the next 8 minutes, then the number of minutes the cheetah have traveled in the second 8 minutes is given by
d = 40/60 x 8 = 5.33 miles
Part E:
The distance the cheetah traveled in the first 8 minutes more than in the second 8 minutes is given by
9.33 miles - 5.33 miles = 4 miles.
Part F:
The ratio of the distance travelled in the first 8 minutes to the distance travelled in the next minutes is given by
9.33 : 5.33 = 1.75 : 1.
Therefore, the distance traveled by the cheetah during the first 8 minutes is 1.75 times greater than the distance traveled during the second 8 minutes.
