5 5/12
(2+3) 1/6 + 1/4=
5 5/12
66.5 square centimeters.
Start by separating the figure into a triangle and a rectangle.
We know the base of the triangle is 7 cm, so find the height by subtracting the total height of the figure by the height of the rectangle. 11 cm - 8 cm = 3 cm
Now, find the area of each shape. The area of a rectangle is length (base) times width (height). This is 7 cm * 8 cm, or 56 cm^2.
Then, find the area of the triangle. The area of a triangle is base times height times 1/2. So, it is 7 cm * 3 cm * 1/2.
21 cm^2 * 1/2
10.5 cm^2
Finally, add the areas together. 56 cm^2 + 10.5 cm^2 = 66.5 cm^2
I believe the following is your problem (if not do rectify me). If so, then:
⁵√x⁴ .⁵√x⁴
1st method:
⁵√x⁴ .⁵√x⁴ = x⁴/⁵ . x⁴/⁵ = x⁽⁴/⁵ +x⁴/⁵⁾ = x⁸/⁵ = ⁵√x⁸ = ⁵√(x⁵.x³) = x. ⁵√x³
2nd method:
⁵√x⁴ . ⁵√x⁴ = ⁵√(x⁴. x⁴) = ⁵√(x⁴⁺⁴) = ⁵√x⁸ = x .⁵√x³
Step-by-step explanation:
To solve an inequality use the following steps: Step 1 Eliminate fractions by multiplying all terms by the least common denominator of all fractions. Step 2 Simplify by combining like terms on each side of the inequality. Step 3 Add or subtract quantities to obtain the unknown on one side and the numbers on the other.
Answer:
Both A and B are true identities
Step-by-step explanation:
A. N ( n − 2 ) ( n + 2 ) = n 3 − 4 n
We need to show that (left-hand-side)L.H.S = R.H.S (right-hand-side)
So,
n ( n − 2 ) ( n + 2 ) = n(n² - 2²) (difference of two squares)
= n³ - 2²n (expanding the brackets)
= n³ - 4n (simplifying)
So, L.H.S = R.H.S
B. ( x + 1 )² − 2x + y² = x² + y² + 1
We need to show that (left-hand-side)L.H.S = R.H.S (right-hand-side)
So,
( x + 1 )² − 2x + y² = x² + 2x + 1 - 2x + y² (expanding the brackets)
= x² + 2x - 2x + 1 + y² (collecting like terms)
= x² + 1 + y²
= x² + y² + 1 (re-arranging)
So, L.H.S = R.H.S
So, both A and B are true identities since we have been able to show that L.H.S = R.H.S in both situations.
