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2 years ago

Rewrite and Order 6/7 and 9/11

Mathematics

1 answer:

Aleksandr-060686 [28]2 years ago

7 0

Answer:

6/7 = 66/77

9/11 = 63/77

6/7 is greater than 9/11

Step-by-step explanation:

To give fractions a common denominator you must find the LCM(lowest common multiple) of this two denominators.

So, we have 7 and 11. You must find a multiple 7 and 11 share. This means that the number must be divisible by 7 and 11. The LCM for 7 and 11 is 77.

Now we make both the denominators 77.

Now look at the numerators. Look at 6/7. We multipled 7 by 11 to get 77. Therefore, we must also multiply 6 by 11.

Now we have, 66/77

Do the same with the other fraction but other way around:

11 x 7 so

9 x 7 = 63

So,

63/77

So 6/7 is now 66/77 and 9/11 is now 63/77

Now compare:

66 > 63

66 is bigger so 6/7 is greater.

6/7 is greater than 9/11

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Which is the equation of the line that passes through the point (-5, -2)

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Answer:

F) y=3x+13

Step-by-step explanation:

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3 years ago

A small military base housing 1,000 troops, each of whom is susceptible to a certain virus infection. Assuming that during the c

slava [35]

Answer:

$I=\frac{1000}{exp^{0,806725*t-0.6906755}+1}$

Step-by-step explanation:

The rate of infection is jointly proportional to the number of infected troopers and the number of non-infected ones. It can be expressed as follows:

$\frac{dI}{dt}=a*I*(1000-I)$

Rearranging and integrating

$\frac{dI}{dt}=a*I*(1000-I)\\\\\frac{dI}{I*(1000-I)}=a*dt\\\\\int\frac{dI}{I*(1000-I)}=\int a*dt\\\\-\frac{ln(1000/I-1)}{1000}+C=a*t$

At the initial breakout (t=0) there was one trooper infected (I=1)

$-\frac{ln(1000/1-1)}{1000}+C=0\\\\-0,006906755+C=0\\\\C=0,006906755$

In two days (t=2) there were 5 troopers infected

$-\frac{ln(1000/5-1)}{1000}+0,006906755=a*2\\\\-0,005293305+0,006906755=2*a\\a = 0,00161345 / 2 = 0,000806725$

Rearranging, we can model the number of infected troops (I) as

$-\frac{ln(1000/I-1)}{1000}+0,006906755=0,000806725*t\\\\-\frac{ln(1000/I-1)}{1000}=0,000806725*t-0,006906755\\-ln(1000/I-1)=0,806725*t-0.6906755\\\\\frac{1000}{I}-1=exp^{0,806725*t-0.6906755} \\\\\frac{1000}{I}=exp^{0,806725*t-0.6906755}+1\\\\I=\frac{1000}{exp^{0,806725*t-0.6906755}+1}$