I wanna say the last one is correct not sure about the others . :\
The probability of four coworkers having different birth months is 0.572 or 55/96
Given there are four coworkers and the condition is they should have different birth months.
As we know probability is the ratio of favorable out comes to the total number of outputs
Favorable outcomes are
For first person 12 months
For second person 11 months
For third person 10 months
For Fourth person 9 months
Total outcomes
For each and every person total outcomes are 12 months which add up to 12 x 12 x 12 x 12 =
Now probability will be
Probability =
Probability = 55/96
Hence the probability of four coworkers having different birth months is 55/96
Learn more about Probability at
brainly.com/question/11234923?referrer=searchResults
#SPJ1
95-88-81-74-67-60-53-46-31-24-17-10
If you turn it around, the rule is add 7 first term 10.
Answer:
24
Step-by-step explanation:
(2(5)+1)+(3(5)-2)
(10+1)+(15-2)
(11)+(13)
24
Answer:
Can I get the full question please
Step-by-step explanation:
x + y = 10 - - - 1
x=2y - - - - - 2
Putting the value of x in eqn 1,
2y+y=10
y=10/3
=3.33 yrs
Which i feel is incorrect