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ale4655 [162]
3 years ago
5

Alex, Bob, and Cole have a combined weight of 111 kilograms. If Alex weighs 44 kg, and Bob weighs three-forth of Alex's weight,

then what is Cole's weight in kilograms?
Mathematics
1 answer:
vlabodo [156]3 years ago
8 0

Answer:34

Step-by-step explanation:

Weight of Alex:44

Weight of Bob:44*(3/4)

=33

Combined weight of all of them:111

Combined weight of Alex and Bob=44+33=77

Cole's weight=111-77 =34

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Say that the economy is in a recession, which is causing the value of gold to fall by three percent. If you have gold reserves w
7nadin3 [17]

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2 years ago
Find MN to the nearest tenth?<br><br> A. 11.34<br> B. 16.1<br> C. 39.6<br> D. 23.8
Nana76 [90]

As the question say this problem is a practice of the law of cosines!

The law of cosine: c^2=a^2+b^2-2ab*cos*c for any side a, b and c

The law can also be written as c=sqrt(a^2+b^2-2abcosc)

Now use this formula!(note cos 100 degrees is about 0.8623)

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5 0
3 years ago
David’s bank offers a 36-month Certificate of Deposit (CD) with an APR of 2.25%. Use the compound interest formula to answer the
tamaranim1 [39]

Using compound interest, it is found that:

a) A(8) = 2389.66

b) t = 31.15

c) P = 1870.85

Compound interest:

A(t) = P\left(1 + \frac{r}{n}\right)^{nt}

  • A(t) is the amount of money after t years.  
  • P is the principal(the initial sum of money).  
  • r is the interest rate(as a decimal value).  
  • n is the number of times that interest is compounded per year.  
  • t is the time in years for which the money is invested or borrowed.

In this problem:

  • The APR is of 2.25%, hence r = 0.0225.
  • No information about the number of compounding per year, hence n = 1.

Item a:

P = 2000, hence:

A(t) = P\left(1 + \frac{r}{n}\right)^{nt}

A(8) = 2000\left(1 + \frac{0.0225}{1}\right)^{8}

A(8) = 2389.66

Item b:

A(t) = 4000, hence:

A(t) = P\left(1 + \frac{r}{n}\right)^{nt}

4000 = 2000\left(1 + \frac{0.0225}{1}\right)^{t}

(1.0225)^t = 2

\log{(1.0225)^t} = \log{2}

t\log{1.0225} = \log{2}

t = \frac{\log{2}}{\log{1.0225}}

t = 31.15

Item c:

A(3) = 2000, hence:

A(t) = P\left(1 + \frac{r}{n}\right)^{nt}

2000 = P\left(1 + \frac{0.0225}{1}\right)^{3}

P = \frac{2000}{(1.0225)^3}

P = 1870.85

A similar problem is given at brainly.com/question/24850750

7 0
2 years ago
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