Halp meh pls :'( (screenshot below)

Mathematics

1 answer:

notsponge [240]3 years ago

8 0

Answer:

the correct answer is answer choixe number 1

You might be interested in

Daisy cut a square out of a sheet of graph paper. The square had an area of 16 square cm. She then trimmed 1 cm from each side o

Degger [83]

Answer: 4 cm^2, it went from 4x4 to 2x2.. clipped on all sides...

Hope I helped!

Giving me brainliest is much appreciated! :).

7 0

3 years ago

Suppose Johnny invests $2,745 into an account, which has been earning interest for many years and he now has a total of $39,974.

Doss [256]

A negative number in this wouldn't be applicable.
Johnny started out with $2,745 in the beginning, EARNING (This being the key word) interest each year. Therefore, he comes out with $39,974, not being a negative number.

Hope I helped! ^-^

5 0

4 years ago

What else would need to be congruent to show that ABC XYZ by ASA?

pochemuha

ASA stands for "angle side side" and we are already given two angles. That means we need a side. That eliminates two of the choices. I would assume that the answer is A, because XY and AB are in between the given angles.

3 0

3 years ago

Read 2 more answers

Please help I ave another one I don't know!!!

Sonbull [250]

Answer:

Step-by-step explanation:

x cannot repeat, look at the others and you will see that x repeats except in D

3 0

3 years ago

Read 2 more answers

Can I get help solving this graph please?

Daniel [21]

see the attached figure with the letters

1) find m(x) in the interval A,B
A (0,100) B(50,40) -------------- > p=(y2-y1(/(x2-x1)=(40-100)/(50-0)=-6/5
m=px+b---------- > 100=(-6/5)*0 +b------------- > b=100
mAB=(-6/5)x+100

2) find m(x) in the interval B,C
B(50,40) C(100,100) -------------- > p=(y2-y1(/(x2-x1)=(100-40)/(100-50)=6/5
m=px+b---------- > 40=(6/5)*50 +b------------- > b=-20
mBC=(6/5)x-20

3) find n(x) in the interval A,B
A (0,0) B(50,60) -------------- > p=(y2-y1(/(x2-x1)=(60)/(50)=6/5
n=px+b---------- > 0=(6/5)*0 +b------------- > b=0
nAB=(6/5)x

4) find n(x) in the interval B,C
B(50,60) C(100,90) -------------- > p=(y2-y1(/(x2-x1)=(90-60)/(100-50)=3/5
n=px+b---------- > 60=(3/5)*50 +b------------- > b=30
nBC=(3/5)x+30

5) find h(x) = n(m(x)) in the interval A,B
mAB=(-6/5)x+100
nAB=(6/5)x
then
n(m(x))=(6/5)*[(-6/5)x+100]=(-36/25)x+120
h(x)=(-36/25)x+120
find <span>h'(x)
</span>h'(x)=-36/25=-1.44

6) find h(x) = n(m(x)) in the interval B,C
mBC=(6/5)x-20
nBC=(3/5)x+30
then
n(m(x))=(3/5)*[(6/5)x-20]+30 =(18/25)x-12+30=(18/25)x+18
h(x)=(18/25)x+18
find h'(x)
h'(x)=18/25=0.72

for the interval (A,B) h'(x)=-1.44
for the interval (B,C) h'(x)= 0.72

<span> h'(x) = 1.44 ------------ > not exist</span>

8 0

3 years ago