Answer:
(y - 1)(5y - 2)
Solution:
Factor:
2 - y(7 - 5y)
Apply the Distributive Property:
2 - 7y + 5y²
Reorder the expression:
5y² - 7y + 2
Rewrite the term:
5y² - 5y - 2y + 2
Regroup terms into two proportional parts:
(5y² - 5y) + ( -2y + 2)
Factor Greatest Common Factors out:
5y(y - 1) - 2(y - 1)
(y - 1)(5y - 2)
Answer:
Compare two multi‐digit numbers based on meanings of the digits in each ... Base 10 blocks are often used in class to help students grasp number. ... Example: Fifteen is 15. ... Example: 14,009: the number name is fourteen thousand, nine ... 12 23. 4 3 2 7 2 3. 2 1 2 5 x 2 x 7 x 2 x 6 x 1 2 x 9 7. 24 161 8 6 4 4,338 4 2 1 7 5.
Step-by-step explanation:
Answer:
The third one
Step-by-step explanation:
Its because we need to find the number that it has grown.
so we add the number that it grew to the size it was before.
Answer: 0.5
Step-by-step explanation:
Given: Rectangle A′B′C′D′ is the image of rectangle ABCD after a dilation.
Since dilation always produces similar images.
To find a scale factor between two similar figures, find two corresponding sides and write the ratio of the two sides.
AB=|-5-(-8)|=|-5+8|=3 units
A'B'=|-2.5-(-4)=|-2.5+4|=1.5 units
The ratio of the corresponding sides A'B' to AB is given by :-

hence, the scale factor of the dilation = 0.5
Step-by-step explanation:
Given the linear equation, y = ⅔x + 1, where the <u>slope</u>, m = ⅔, and the y-intercept, (0, 1) where<em> b</em> = 1.
<h3><u>Start at the y-intercept:</u></h3>
In order to graph the given linear equation, start by plotting the coordinates of the y-intercept, (0, 1). As we know, the <u>y-intercept</u> is the point on the graph where it crosses the y-axis. It coordinates are (0, <em>b</em>), for which the value of b represents the value of the y-intercept in slope-intercept form, y = mx + b.
<h3><u>Plot other points using the slope:</u></h3>
From the y-intercept, (0, 1), we must use the slope, m = ⅔ (<em>rise</em> 2, <em>run</em> 3) to plot the other points on the graph. Continue the process until you have sufficient amount of plotted points on the graph that you could connect a line with.
Attached is a screenshot of the graphed linear equestion, which demonstrates how I plotted the other points on the graph using the "rise/run" techniques" discussed in the previous section of this post.