Answer:
Explanation:
The cell membrane separates the cell from the outer environment. The extracellular fluid contains the sodium ions (Na+), chloride ions (Cl-), while intracellular fluid contains potassium (K +) and negative anions.
The potential difference arises when the membrane is selectively permeable to some ions. The resting potential is -70mV.
When the neurons get excited, the sodium ions start to enter by sodium channels.
Now there are more positive ions inside the cell membrane. It disturbs the resting potential i.e. -70mV. This stage is known as depolarization.
When the inside environment of the cell is more positively charged, the potassium ions start to move out of the cell. It goes out by the voltage-gated channels. Thus resting stage is maintained and it is known as repolarization.
But the initial stability of the cell membrane has to be maintained. To restore the resting stage, the sodium ions start to move out of the membrane and potassium ions enter into the cells again. This is an active transport and has done by the Na+ - K+ pump. Here 3 sodium ions move out and 2 potassium ions pumped into the cell through the plasma membrane.
Thus the resting potential regains. The potassium ions come back into the cells against the concentration gradient and ATP provides the energy for this phenomena.
<h2>ANSWER</h2>
When chemical communication at a synapse is terminated by the recapture of neurotransmitter molecules by the presynaptic neuron, we refer to the process as <u>Reuptake.</u>
<h3>#CarryOnLearning</h3>
The answer is hydrogen and oxygen
<u><em>My answer is that this statement is false.</em></u>
Answer:
The correct answer is A the compound is a competitive inhibitor
Explanation:
Competitive inhibitor competes with the substrate to bind to the active site of the target enzyme and after binding to the active site the inhibitor slow down or stop the reaction catalyzed by that enzyme.
Competitive inhibitor basically effects the Km value of the enzyme thus decreasing the activity of the later.
Increasing the substrate concentration displace the inhibitor from the enzyme"s active site thus reducing the inhibitory effects of the later thus increasing the activity of the enzyme.
