A simple random sample of size nequals57 is obtained from a population with muequals69 and sigmaequals2. Does the population nee
d to be normally distributed for the sampling distribution of x overbar to be approximately normally distributed? Why? What is the sampling distribution of x overbar?
1 answer:
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Answer:
14.25 - d
Step-by-step explanation:

Actually Welcome to the concept of expo functions.
f(x) = -8(2)^x - 12 ,
for f(0) ,here substitute x = 0
so we get as ,
==> f(0) = -8(2)^0 -12
==> f(0) = -8-12
==> f(0) = -20
hence, f(0) = -20
Looks like y = |x| because the slopes of the lines are both 1
You shift it to the right making it |x-2| and you shift it down making y = -2
combine to get <em>y = |x - 2| - 2</em>.
23. it increased by 12 because the difference between -4 and 8 is 12
24. 25 because 40 minus 15 is 25
26. 5 because 156 minus 96 equals 60 and 60 divided by 12 equals 5
To solve this problem you need to know the law of cosines.