All categories

3 years ago

I need to know how to solve this chemical equation

Chemistry

1 answer:

Vlad1618 [11]3 years ago

6 0

I’m pretty sure you just balance it out

You might be interested in

Why do we need to balance chemical equations?

Mrrafil [7]

So we know the number of moles of each compound. If we need to know the concentration we must know the number of moles that the compounds react with...

8 0

4 years ago

Read 2 more answers

A 2.5 L flask is filled with 0.25 atm SO3, 0.20 atm SO2, and 0.40 atm O2, and allowed to reach equilibrium. Assume at the temper

Anit [1.1K]

Explanation:

Reaction equation for the given chemical reaction is as follows.

$2SO_{3} \rightleftharpoons 2SO_{2} + O_{2}$

Equation for reaction quotient is as follows.

Q = $\frac{P^{2}_{SO_{2}} \times P_{O_{2}}}{P^{2}_{SO_{3}}}$

= $\frac{(0.20)^{2} \times 0.40}{(0.25)^{2}}$

= 0.256

As, Q > K (= 0.12)

The effect on the partial pressure of $SO_{3}$ as equilibrium is achieved by using Q, is as follows.

This means that there are too much products.

Equilibrium will shift to the left towards reactants.

More $SO_{3}$ is formed.

Partial pressure of $SO_{3}$ increases.

4 0

3 years ago

Helppppppppppp please

valentinak56 [21]

Your answer would have to be #3

4 0

4 years ago

If a plane is traveling300 mph how long will it take to travel 1800 miles

bonufazy [111]

My calculations say it'll take 600 hours???

5 0

3 years ago

If it takes 5 hours to produce 8.0 kg of alcohol, how any days will it take to consume 1000 kg of glucose?

Ipatiy [6.2K]

It takes 21.3 days

<h3>Further explanation</h3>

Given

5 hr = 8 kg Alcohol

Required

Days to consume 1000 kg of glucose

Solution

Alcoholic fermentation⇒ glucose produces ethanol and carbon dioxide,

C₆H₁₂O₆ → 2 C₂H₅OH + 2CO₂

mol ethanol :

$\tt \dfrac{5000~g}{46~g/mol}=108.7~moles$

moles of glucose to produce 108.7 moles ethanol :

$\tt \dfrac{1}{2}\times 108.7=54.35$

54.35 moles = 5 hours

moles of 1000 kg of glucose :

$\tt \dfrac{10^6~g}{180~g/mol}=5555.5~moles$

So for 5555.5 moles, it takes :

$\tt \dfrac{5555.5}{54.35}\times 5~hours=511.085~h=21.3~days$

7 0

4 years ago