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MArishka [77]
3 years ago
9

Students conduct an experiment in which steel wool is burned in a closed test tube. The steel wool reacts with an amount of oxyg

en equal to 1.43% of the mass of the steel wool. What is the correct value for the missing mass in the table?
Chemistry
2 answers:
Ksenya-84 [330]3 years ago
6 0
The answer is 43.48g
Lubov Fominskaja [6]3 years ago
6 0

The value of the mass in the missing table is 43.48 g. Since it is in a closed system, nothing would escape. The law of conservation of mass would state that the products mass would equal the reactants mass.

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What is the standard electrode potential for a galvanic cell constructed in the appropriate way from these two half-cells?
____ [38]

E

θ

Cell

=

+

2.115

l

V

Cathode

Mg

2

+

/

Mg

Anode

Ni

2

+

/

Ni

Explanation:

Look up the reduction potential for each cell in question on a table of standard electrode potential like this one from Chemistry LibreTexts. [1]

Mg

2

+

(

a

q

)

+

2

l

e

−

→

Mg

(

s

)

−

E

θ

=

−

2.372

l

V

Ni

2

+

(

a

q

)

+

2

l

e

−

→

Ni

(

s

)

−

E

θ

=

−

0.257

l

V

The standard reduction potential

E

θ

resembles the electrode's strength as an oxidizing agent and equivalently its tendency to get reduced. The reduction potential of a Platinum-Hydrogen Electrode under standard conditions (

298

l

K

,

1.00

l

kPa

) is defined as

0

l

V

for reference. [2]

A cell with a high reduction potential indicates a strong oxidizing agent- vice versa for a cell with low reduction potentials.

Two half cells connected with an external circuit and a salt bridge make a galvanic cell; the half-cell with the higher

E

θ

and thus higher likelihood to be reduced will experience reduction and act as the cathode, whereas the half-cell with a lower

E

θ

will experience oxidation and act the anode.

E

θ

(

Ni

2

+

/

Ni

)

>

E

θ

(

Mg

2

+

/

Mg

)

Therefore in this galvanic cell, the

Ni

2

+

/

Ni

half-cell will experience reduction and act as the cathode and the

Mg

2

+

/

Mg

the anode.

The standard cell potential of a galvanic cell equals the standard reduction potential of the cathode minus that of the anode. That is:

E

θ

cell

=

E

θ

(

Cathode

)

−

E

θ

(

Anode

)

E

θ

cell

=

−

0.257

−

(

−

2.372

)

E

θ

cell

=

+

2.115

Indicating that connecting the two cells will generate a potential difference of

+

2.115

l

V

across the two cells.

5 0
2 years ago
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podryga [215]

Answer:

c

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What is the charge on an atom with an equal number of protons and electrons?
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Answer:

1) SO₄ ²⁻ : (+6)

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Explanation:

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Sulfate (SO₄ ²⁻), the most oxidized form of sulfur (+6), <u>is reduced</u> by these

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b) The net ionic equation under acidic conditions is:

              4 H₂ + SO₄²⁻ + H⁺ → HS⁻ + 4 H₂O

    Global reaction:  SO₄²⁻ + 2H⁺ → H₂S + O₂

3 0
2 years ago
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