Answer:
-3.82ºC is the freezing point of solution
Explanation:
We work with the Freezing point depression to solve the problem
ΔT = m . Kf . i
ΔT = Freezing point of pure solvent - freezing point of solution
Let's find out m, molality (moles of solute in 1kg of solvent)
15 g / 58.45 g/mol = 0.257 moles of NaCl
NaCl(s) → Na⁺ (aq) + Cl⁻(aq)
i = 2 (Van't Hoff factor, numbers of ions dissolved)
m = mol /kg → 0.257 mol / 0.250kg = 1.03 m
Kf = Cryoscopic constant → 1.86 ºC/m (pure, for water)
0ºC - Tºf = 1.03m . 1.86ºC/m . 2
Tºf = -3.82ºC
Cells have many structure inside of them called organelles which allow it to function and survive
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The question above can be answered by using the volume balance concept. Two equations can be established by total volume balance and the component (acid) volume balance.
If we let x be the volume of the 12% acid solution, the volume of the 20% acid solution will have to be 100 - x.
x + (100 - x) = 100
Then, the acid mass balance will give us the equation,
(x)(0.12) + (100 - x)(0.20) = (100)(0.18)
Simplifying,
0.12x + 20 - 0.20x = 18
-0.08x = 20 - 18
-0.08x = 2
The value of x from the equation is 25.
<em>Hence, the volume of the 12% acid solution is 20 galloons and that of the 20% acid solution is 75 galloons. </em>
Answer:
The nucleus contains all of the genetic material for a eukaryotic cell, but this genetic material needs to be protected.
Explanation:
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