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bixtya [17]
3 years ago
9

If a uranium atom undergoes both alpha and gamma decay, what happens to it?

Chemistry
2 answers:
WARRIOR [948]3 years ago
5 0

If a uranium atom undergoes both alpha and gamma decay, then it means that there will be formation of one helium particle which is also known as alpha particle and gamma decay is the radiation or release of energy. Whereas in a radioactive reaction, Uranium-235 absorbs a neutron and splits into two new atoms.

hope this helps

Alex_Xolod [135]3 years ago
5 0

Answer: _{92}^{235}\textrm{U}+_0^1\textrm{n}\rightarrow _{56}^{143}Ba+_{36}^{90}Kr+3_0^1\textrm{n}

Explanation: Nuclear fission : It is a process which involves the conversion of a heavier nuclei into two or more small and stable nuclei along with the release of energy.

General representation of an element is given as:   _Z^A\textrm{X}

where,

Z represents Atomic number

A represents Mass number

X represents the symbol of an element

Alpha decay : When a larger nuclei decays into smaller nuclei by releasing alpha particle. In this process, the mass number and atomic number is reduced by 4 and 2 units respectively.

Gamma radiations does not carry any charge and are electrically neutral.

The equation for the decay will be written as:_{92}^{235}\textrm{U}+_0^1\textrm{n}\rightarrow _{56}^{143}Ba+_{36}^{90}Kr+3_0^1\textrm{n}

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3 years ago
For a first-order reaction, A → B, the rate coefficient was found to be 3.4 × 10-4 s-1 at 23 °C. After 5.0 h, the concentration
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Answer:

the original concentration of A = 0.0817092  M

Explanation:

A reaction is considered to be of first order it it strictly obeys the graphical equation method.

k_1 = \dfrac{2.303}{t}log \dfrac{a}{a-x}

where;

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a - x = remaining concentration of initial concentration at time t = 0.00018 mol L⁻¹

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3.4 \times 10^{-4}= 1.27944 \times 10^{-4} \times log \dfrac{a}{0.00018}

\dfrac{3.4 \times 10^{-4}}{1.27944 \times 10^{-4}}=   log \dfrac{a}{0.00018}

2.657=   log \dfrac{a}{0.00018}

10^{2.657}= \dfrac{a}{0.00018}

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a =453.94 \times 0.00018

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Thus , the original concentration of A = 0.0817092  M

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