The similar circles P and Q can be made equal by dilation and translation
- The horizontal distance between the center of circles P and Q is 11.70 units
- The scale factor of dilation from circle P to Q is 2.5
<h3>The horizontal distance between their centers?</h3>
From the figure, we have the centers to be:
P = (-5,4)
Q = (6,8)
The distance is then calculated using:
d = √(x2 - x1)^2 + (y2 - y1)^2
So, we have:
d = √(6 + 5)^2 + (8 - 4)^2
Evaluate the sum
d = √137
Evaluate the root
d = 11.70
Hence, the horizontal distance between the center of circles P and Q is 11.70 units
<h3>The scale factor of dilation from circle P to Q</h3>
We have their radius to be:
P = 2
Q = 5
Divide the radius of Q by P to determine the scale factor (k)
k = Q/P
k = 5/2
k = 2.5
Hence, the scale factor of dilation from circle P to Q is 2.5
Read more about dilation at:
brainly.com/question/3457976
Even integers are in form 2n where n is a whole number
consecutive even integers are 2 apart
2n and 2n+2
2n is 10 more than 1/2 of (2n+2)
2n=10+1/2(2n+2)
2n=10+n+1
2n=11+n
minus n both sides
n=11
2n=22
2n+2=24
the numbers are 22 and 24
Y=50+.05x
Just plug in the number of texts for x
y=50+.05(25)
y=51.25
^That was for 25 texts
Now just plug in all the other texts and replace that with x
Hope this helps!
0.0069
Step-by-step explanation:
6.9 move the decimal 3 places to the left
Answer:
Step-by-step explanation:
