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aleksklad [387]
3 years ago
12

A box contains 7 plain pencils and 5 pens. A second box contains 5 color pencils and 5 crayons. One item from each box is chosen

at random. What is the probability that a pen from the first box and a crayon from the second box are selected?
Mathematics
1 answer:
Nastasia [14]3 years ago
4 0
7 + 5 to get your total for rhe first box so 12 is your denominator for the first box, and there are 5 pens so the fraction is 5/12 for the first one.

For the second box you do it the same way you did the first but with its number instead so 5 + 5 which is 10 so thats your denominator and your number of your crayons which is 5 is on top. So your fraction for the second box is 5/10 which simplifies to 1/2. But if you have to get only one fraction add them together and you get 55/60 which simplifies to 11/12.
Hope this helped!
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keeping in mind that parallel lines have the same exact slope, hmmmm what's the slope of the line above anyway?

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\bf (\stackrel{x_1}{18}~,~\stackrel{y_1}{2})~\hspace{10em} \stackrel{slope}{m}\implies \cfrac{1}{3} \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{2}=\stackrel{m}{\cfrac{1}{3}}(x-\stackrel{x_1}{18}) \\\\\\ y-2=\cfrac{1}{3}x-6\implies y=\cfrac{1}{3}x-4

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