Answer: 118
Explanation:
Since ∠A=∠ADB: ∠ADB=61°. The sum of the interior angles of any triangle is 180°, thus:
61°+61°= 122
180-122=58°
∠DBA=58°
Since triangle BCD is an equilateral triangle, all the interior angles are the same:
180/3=60
∠DBC=60°
∠BCD=60°
∠CDB=60°
Since angles DBC and DBA make up angle ABC, just simply add the two angles together:
58+60=118°
Therefore, ∠ABC is 118°.
Answer:
y = 4x + -9
Step-by-step explanation:
The y intercept which is -9, is the point in which the graph crosses the x-axis
In order to find the slope we need to identify two clear points on the graph.
- (0, -9)
- ( 1, -5)
Now that we have our two points we need to find the distance between them.
As you can see on the attachment the distance between the two points is 4 units up and 1 unit to the right, therefore the slope is 4/1 = 4.
Final Answer: y = 4x + -9
Answer:
y = -4x² + 32x - 48
Step-by-step explanation:
The standard form of a quadratic equation is
y = ax² + bx + c
We must find the equation that passes through the points:
(2, 0), (6,0), and (3, 12)
We can substitute these values and get three equations in three unknowns.
0 = a(2²) + b(2) + c
0 = a(6²) + b(6) + c
12 = a(3²) + b(3) + c
We can simplify these to get the system of equations:
(1) 0 = 4a + 2b + c
(2) 0 = 36a + 6b + c
(3) 12 = 9a + 3b + c
Eliminate c from equations (1) and (2). Subtract (1) from (2).
(4) 0 = 32a + 4b
Eliminate c from equations (2) and (3). Subtract (3) from (2).
(5) -12 = 27a - 3b
Simplify equations (4) and (5).
(6) 0 = 8a + b
(7) -4 = 9a - b
Eliminate b by adding equations (6) and (7).
(8) a = -4
Substitute (4) into (6).
0 = -32 + b
(9) b = 32
Substitute a and b into (1)
0 = 4(-4) + 2(32) + c
0 = -16 + 64 + c
0 = 48 + c
c = -48
The coefficients are
a= -4, b = 32, c = -48
The quadratic equation is
y = -4x² + 32x - 48
The diagram below shows the graph of your quadratic equation and the three points through which it passes.