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mart [117]
2 years ago
12

What number represents 100% of the fall student athlete

Mathematics
2 answers:
mylen [45]2 years ago
7 0

Answer:

140.

Step-by-step explanation:

We have been given a diagram. We are asked to find the number that represents 100% of the fall student athlete.

To find the number of students that represents 100% of the fall student athlete, we will add numbers of students is each fall sport.

\text{Number that represents }100\%\text{ of the fall student athlete}=12+21+62+45

\text{Number that represents }100\%\text{ of the fall student athlete}=140

Therefore, 140 students represent 100% of the fall student athlete.

natta225 [31]2 years ago
6 0

Answer:

62

Step-by-step explanation:

this is because 62 might be 100%

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Answer:

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2 years ago
Can someone help me thx
VikaD [51]
Answer: 118



Explanation:

Since ∠A=∠ADB: ∠ADB=61°. The sum of the interior angles of any triangle is 180°, thus:

61°+61°= 122
180-122=58°
∠DBA=58°

Since triangle BCD is an equilateral triangle, all the interior angles are the same:

180/3=60
∠DBC=60°
∠BCD=60°
∠CDB=60°

Since angles DBC and DBA make up angle ABC, just simply add the two angles together:

58+60=118°

Therefore, ∠ABC is 118°.
7 0
2 years ago
Find the equation of the line.<br> Use exact numbers.
Citrus2011 [14]

Answer:

y = 4x + -9

Step-by-step explanation:

The y intercept which is -9, is the point in which the graph crosses the x-axis

In order to find the slope we need to identify two clear points on the graph.

- (0, -9)

- ( 1, -5)

Now that we have our two points we need to find the distance between them.

As you can see on the attachment the distance between the two points is 4 units up and 1 unit to the right, therefore the slope is 4/1 = 4.

Final Answer: y = 4x + -9

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Determine an equation of a Quadratic function
Pepsi [2]

Answer:

y = -4x² + 32x - 48

Step-by-step explanation:

The standard form of a quadratic equation is  

y = ax² + bx + c

We must find the equation that passes through the points:

(2, 0), (6,0), and (3, 12)

We can substitute these values and get three equations in three unknowns.

0 = a(2²) + b(2) + c

0 = a(6²) + b(6) + c

12 = a(3²) + b(3) + c

We can simplify these to get the system of equations:

(1)   0 =    4a + 2b + c

(2)  0 = 36a + 6b + c

(3) 12 =   9a + 3b + c

Eliminate c from equations (1) and (2). Subtract (1) from (2).

(4) 0 = 32a + 4b

Eliminate c from equations (2) and (3). Subtract (3) from (2).

(5) -12 = 27a - 3b

Simplify equations (4) and (5).

(6)  0 = 8a + b

(7) -4 = 9a  - b

Eliminate b by adding equations (6) and (7).

(8) a = -4

Substitute (4) into (6).

    0 = -32 + b

(9) b =  32

Substitute a and b into (1)

0 = 4(-4) + 2(32) + c

0 = -16 + 64 + c

0 = 48 + c

c = -48

The coefficients are

a= -4, b = 32, c = -48

The quadratic equation is

y = -4x² + 32x - 48

The diagram below shows the graph of your quadratic equation and the three points through which it passes.

4 0
3 years ago
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