Answer:
5
Step-by-step explanation:
a=12 (height)
c=13 (hypotenous)
b=? (base)
By using Pythagoras theorm
We have, hypotenous sq=base sq+height sq
Let b =base SO, base sq=hypotenous Sq-height Sq
=>base Sq =13sq-12sq
Base Sq =169-144
Base Sq =25
Base =5 (shifting the sq)....
Hope it's helpful
Answer: the second one
Step-by-step explanation:
The LCM of 6 and 4 is 12. The LCM of 6 and 8 is 24. The LCM of 6 and 10 is 30.
To find the LCM, we find the prime factorization of each number.
6 = 2*3
4 = 2*2
They have a 2 in common, so this is one factor of the LCM. We then take the uncommon factors, 3 and 2, giving us
2*3*2 = 12.
6 = 2*3
8 = 2*2*2
LCM = 2 (in common) * 3 * 2 * 2 (uncommon) = 24.
6 = 3*2
10 = 5*2
LCM = 2 (in common) * 3 * 5 (uncommon) = 30.
Answer:
The third side is sqrt(77)
Step-by-step explanation:
Since this is a right triangle we can use the Pythagorean theorem
a^2 + b^2 = c^2 where a and b are the legs and c is the hypotenuse
2^2 + b^2 = 9^2
4+ b^2 = 81
Subtract 4 from each side
b^2 = 81-4
b^2=77
Take the square root of each side
sqrt(b^2) = sqrt(77)
b = sqrt(77)
The third side is sqrt(77)
