3v + 6v(4v - 2v)
3v + 6v(2v)
3v + 12v²
3v(4v + 1) is your answer
hope this helps
Zero cannot be a denominator.
You need to find points where the line g(x) intercepts the quadratic function f(x) in one and only one point.
Then 3x^2 + 4x -2 = mx - 5
solve 3x^2 + 4x - mx -2 + 5 = 0
3x^2 + (4 - m)x + 3 = 0
In order to there be only one solution (one intersection point) the radicand of the quadratic formula must be 0 =>
b^2 - 4ac = (4 - m)^2 - 4(3)(3) = 0
(4 - m)^2 = 24
4 - m = +/- √(24)
m = 4 +/- √(24) = 4 +/- 2√(6)
Then m, the slope of the line, may be 4 + 2√6 and 4 - 2√6
Answer:
x=20
Step-by-step explanation:
First, find LJ
Angle L = 60 (180 - 30 - 90)
The cosine of an angle is equal to the ratio of the adjacent side to the hypotenuse.
cos(L)=adj/hyp
cos(60)=LJ/40√2
LJ = cos(60)*40√2
LJ = 20√2
Now you can use LJ to find x. You also know the value of each angle, 45
x=20√2⋅cos(45)
x=20
It looks like it is -1 chief