Answer:
Energy cannot be converted from one form to another.
Answer:
a. [Na₂CrO₄] = 0.10 M
b. 0.017 moles of KBr
Explanation:
Molarity means a sort of concentration which indicates the moles of solute over 1L of solution.
We determine the moles of solute: 12.5 g / 162g/mol = 0.0771 moles
We convert the volume of solution from mL to L = 750 mL . 1L/1000mL = 0.750L
Molarity (mol/L) → 0.0771 mol / 0.750L = 0.10 M
b. In order to determine the moles of solute, with the molarity of solution and the volume we assume:
Molarity = moles of solute /volume of solution
Then, Molarity . Volume of solution (L) = moles of solute
We convert the volume of solution from mL to L = 150 mL . 1L/1000mL = 0.150L
0.112 mol/L . 0.150L = Moles of solute → 0.017 moles of KBr
Scientists often communicate their research results in three general ways. but this only asks for 2 so I'm giving 2 haah anyway .One is to publish their results in peer reviewed journals that can be ready by other scientists. Two is to present their results at national and international conferences where other scientists can listen to there presentations or presentations in general.
hope this helped
Answer:
0.42 M
Explanation:
The reaction that takes place is:
- Cu(CH₃COO)₂ + Na₂CrO₄ → Cu(CrO₄) + 2Na(CH₃COO)
First we <u>calculate the moles of Na₂CrO₄</u>, using the <em>given volume and concentration</em>:
(200 mL = 0.200L)
- 0.70 M * 0.200 L = 0.14 moles Na₂CrO₄
Now we <u>calculate the moles of Cu(CH₃COO)₂</u>, using its <em>molar mass</em>:
- 40.8 g ÷ 181.63 g/mol = 0.224 mol Cu(CH₃COO)₂
Because the molar ratio of Cu(CH₃COO)₂ and Na₂CrO₄ is 1:1, we can directly <u>substract the reacting moles of Na₂CrO₄ from the added moles of Cu(CH₃COO)₂</u>:
- 0.224 mol - 0.14 mol = 0.085 mol
Finally we <u>calculate the resulting molarity</u> of Cu⁺², from the <em>excess </em>cations remaining:
- 0.085 mol / 0.200 L = 0.42 M
The answer is 1, 1 , 1 because that will balance out the equation and make them equal
