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2 years ago

For each of the following atomic numbers, use the periodic

Chemistry

1 answer:

Cerrena [4.2K]2 years ago

6 0

The ions in a formed;

13 - Al - Al^3+
34 - Se - Se^2-
56 - Ba - Ba^2+
7 - N - N^3-
87 - Fr - Fr^+
35 - Br - Br^-

<h3>What is the atomic number?</h3>

The atomic number is the number of protons in an atom. It is also the number electrons in the neutral atom. Now we know that when an ion is formed, electrons are lost or gained by the atom.

Let us now write the ions that are formed by each of the atoms of elements that have the atomic number as listed;

13 - Al - Al^3+
34 - Se - Se^2-
56 - Ba - Ba^2+
7 - N - N^3-
87 - Fr - Fr^+
35 - Br - Br^-

Learn more about atomic number:brainly.com/question/16858932

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3 years ago

Ideal gas (n 2.388 moles) is heated at constant volume from T1 299.5 K to final temperature T2 369.5 K. Calculate the work and h

bija089 [108]

Answer : The work, heat during the process and the change of entropy of the gas are, 0 J, 3333.003 J and -10 J respectively.

Explanation :

(a) At constant volume condition the entropy change of the gas is:

$\Delta S=-n\times C_v\ln \frac{T_2}{T_1}$

We know that,

The relation between the $C_p\text{ and }C_v$ for an ideal gas are :

$C_p-C_v=R$

As we are given :

$C_p=28.253J/K.mole$

$28.253J/K.mole-C_v=8.314J/K.mole$

$C_v=19.939J/K.mole$

Now we have to calculate the entropy change of the gas.

$\Delta S=-n\times C_v\ln \frac{T_2}{T_1}$

$\Delta S=-2.388\times 19.939J/K.mole\ln \frac{369.5K}{299.5K}=-10J$

(b) As we know that, the work done for isochoric (constant volume) is equal to zero. $(w=-pdV)$

(C) Heat during the process will be,

$q=n\times C_v\times (T_2-T_1)=2.388mole\times 19.939J/K.mole\times (369.5-299.5)K= 3333.003J$

Therefore, the work, heat during the process and the change of entropy of the gas are, 0 J, 3333.003 J and -10 J respectively.

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3 years ago

6.201cm+7.4cm+0.68 cm+12.0cm

zimovet [89]

If you want the answer is centimeters is it going to be:
26.281 cm
If it make it easier for you to solve add 6.201 and 7.4 which will equal 13.601. Then add .68 to 13.601 which equals 14.281. Last add 12 to 14.281 which equals 26.281.

Hope this helps.

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3 years ago