I need help with homework

After 24 pencil had sharpened, the pencil sharpener receptacle is full. If receptacle is emptied in average of twice a day, how

stiks02 [169]

Answer:

12 Pencils Sharpened

Step-by-step explanation:

Since the sharpener receptacle is emptied out 2 times every day.

Do 24*2 to get 48 pencils sharpened each day.

Now do 48/20 to get how many pencils a single person sharpens each day. Resulting in 2.4 pencils each day for 1 person.

Multiple 2.4 by 5 (Amount of days) to get 12 pencils in 5 days.

4 0

3 years ago

Hey guys! I’m having a lot of trouble with this paper, would anyone mind explaining one of them to me?

lyudmila [28]

Answer: See Explanation

Step-by-step explanation:

This worksheet seems to be about "Special Right Triangles"

In this worksheet, it instructs you to find the missing side lengths.

Explaining number 1)

Step 1) Identifying the triangle and what it means

Since the triangle in number one is a 45-45-90 triangle with the given side length of "1" on one of the legs of the triangle, it can be concluded that the other leg also has a side length of "1" (due to the ratio of side on a 45-45-90 degree triangle), is also states the triangle has 45 degrees labeled on one of the angles, is can also be concluded that the other missing angle is 45 degrees.

Step 2) Answer

The answer to b is 1 and the answer to a is square root of 2, due to the properties of a 45 45 90 triangle (refer attachment)

*you can also use the following attachment to help you on this problem

7 0

3 years ago

Formúla General a) 4x²=9x-2=0 b) X²+8x-84=0

makkiz [27]

Answer: a) $x=\dfrac{-9 \pm\sqrt{113} }{8}$

b) x₁ = - 14; x₂ = 6.

Step-by-step explanation:

a) 4x² + 9x - 2 = 0

$x=\dfrac{-b \pm \sqrt{b^{2}-4ac } }{2a} \\\\a=4; \: \: b=9; \: \: c=-2\\x =\dfrac{-9 \pm \sqrt{9^{2}-4 \cdot 4 \cdot (-2) } }{2 \cdot 4} =\dfrac{-9 \pm\sqrt{113} }{8}$

b) x² + 8x - 84 = 0

$x=\dfrac{-b \pm \sqrt{b^{2}-4ac } }{2a} \\\\a=1; \: \: b=8; \: \: c=-84\\\\x =\dfrac{-8 \pm \sqrt{8^{2}-4 \cdot 1 \cdot (-84) } }{2 \cdot 1} =\dfrac{-8 \pm\sqrt{400} }{2}=\dfrac{-8 \pm 20}{2} =-4 \pm 10\\\\x_{1} =-14\\x_{2} =6$