You want to find values of v (number of visors sold) and c (number of caps sold) that satisfy the equation
... 3v + 7c = 4480
In intercept form, this equation is
... v/(1493 1/3) + c/640 = 1 . . . . . divide by 4480
Among other things, this tells us one solution is
... (v, c) = (0, 640)
The least common multiple of 3 and 7 is 21, so decreasing the number of caps sold by some multiple of 3 and increasing the number of visors sold by that same multiple of 7 will result in another possible solution.
The largest multiple of 21 that is less than 4480 is 213. Another possible solution is (0 +213·7, 640 -213·3) = (1491, 1)
We can also pick some number in between, say using 100 as the multiple
... (0 +100·7, 640 -100·3) = (700, 340)
In summary, your three solutions could be
... (visors, caps) = (0, 640), (700, 340), (1491, 1)
a.
Let
5x = number of games won
2x = number of games lost
The total number of win and lose is 154. So
5x + 2x = 154
Solving for x,
7x = 154
x = 22
Therefore, the number of games won is 5*22=110 and the number of games lost is 2*22 is 44.
b.
Let
6x = first side of the triangle
7x = second side of the triangle
9x = third side of the triangle
The perimeter of a triangle is the total of all sides. So,
6x + 7x + 9x = 88
22x = 88
x = 4
Therefore, the three lengths of the side are 6*4=24, 7*4=28, and 9*4 = 36
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Answer:
9.76
Step-by-step explanation:
area of a rectangle = length * breadth
length = (2x + 3)
breadth = x
given area is 220 sq. inches.
thus,
220 = x * (2x+3)
220 = 2x² +3x
2x² + 3x -220 = 0
x = (-b + √ ( b²-4ac) ) ÷ 2a
x = ( -3 + √ ( 3² - 4*2*220) ) ÷ 2*2
x =9.76
Bob = 12 x T
Sue= 8 (T +2)
12T = 8T + 16
12T-8T=8T-8T +16
4T = 16
4T/4 = 16/4
T= 4 HOURS
PLUG T BACK INTO
12(4) = 8(4) + 16
48=48
DISTANCE = 48 kilometers
Cos m = .4685
cos^-1(.4685) = 62 degrees
angle L = 180-90-62 = 28 degrees
