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Ivanshal [37]
3 years ago
13

What is the answer to the meeting had 30 people, which is five-sixths of the club. how many people are in the club?

Mathematics
1 answer:
netineya [11]3 years ago
5 0
36 people in the club
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Can someone help me with this please?
garri49 [273]

Answer:

EASY PEASY

Step-by-step explanation:

(5x-5)=(4x+10){being corresponding angles}

solve it now by arranging like

5x-4x=10+5

done

and the second is co-interior

8 0
3 years ago
Find the reference angle for 4pi/7
Alex17521 [72]

Find the Reference Angle (4pi)/7 4π 7 4 π 7 Since the angle 4π 7 4 π 7 is in the second quadrant, subtract 4π 7 4 π 7 from π π.

Thus, \frac{3\pi }{7} is your answer

8 0
3 years ago
after five years of earning interest at an annual rate of 4% and investment has earned $1,200 in interest determine the amount o
loris [4]

Answer:

$6000

Step-by-step explanation:

$1200/5years =$240/1yr

$240=4%

:. 1%=$60

Initial investment =$60*100%=$6000

6 0
4 years ago
PLEASE HELP WILL GIVE BRAINLIEST!!!!!!!!!!!!!!!!!!!!!!!!
STatiana [176]

Considering High School level question, answer can be written as:


A system of 2 linear equations is [two] dimensional. It is a graph of [two] lines. The solutions can be [unique] solution if the graph intersects. [No] solution if the lines are parallel - meaning they have the same slope, or [Infinitely many] solutions if they are the same line.


Explanation:

when two lines are drawn on a two-dimensional plane then there are only three possible cases:

Case1: lines will intersect

In that case you will get a unique solution at the intersection point.


Case2: lines are parallel but don't touch each other

In that case there will be no point which lies on both lines so No solution.


Case3: lines are overlapping.

In that case all the points lies on both lines so infinitely many solutions.


6 0
4 years ago
Right in equation that shows the relationship between time and distance use your equation to find out how long it would take in
Naddika [18.5K]
This couldn't be answered!
4 0
3 years ago
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