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lubasha [3.4K]
4 years ago
5

PLEASE HELP!!

Mathematics
2 answers:
Alborosie4 years ago
7 0

Answer:

A

Step-by-step explanation:

svlad2 [7]4 years ago
7 0

Answer:

Option A

Step-by-step explanation:

We have to find the limit of the function (x² + 3x - 1) as x approaches 3.

lim[f(x)] = lim (x² + 3x -1)

x⇒3         x⇒3

            = (3)² + (3 × 3) -1

            = 9 + 9 - 1

            = 18 - 1

            = 17

Option A is the answer.

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Please help me! So confused on the difference between the two and how to work them out!​
wlad13 [49]

Answer:

A. 45

B. 684

The Least Common Multiple ( LCM ) is also referred to as the Lowest Common Multiple ( LCM ) and Least Common Denominator ( LCD) . For two integers a and b, denoted LCM(a,b), the LCM is the smallest integer that is evenly divisible by both a and b.

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7 0
4 years ago
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Michael owns dogs hamsters and fish in the ratio 2:3:6 he has 2 more hamsters than dogs how many fish does Michael have
IRISSAK [1]
12 because 6 is 2 more than 4 which means you would have to add everything by themselves so 2 would be 4 3 would be 6 and 6 would be 12
8 0
3 years ago
Which of the following is a solution to 2cos2x − cos x − 1 = 0?
Pavel [41]

Answer:

Option A is correct.

Solution for the given equation is, x = 0^{\circ}

Step-by-step explanation:

Given that : 2\cos^2x -\cos x -1 =0

Let \cos x =y

then our equation become;

2y^2-y-1= 0           .....[1]

A quadratic equation is of the form:

ax^2+bx+c =0.....[2] where a, b and c are coefficient and the solution is given by;

x = \frac{-b\pm \sqrt{b^2-4ac}}{2a}

Comparing equation [1] and [2] we get;

a = 2 b = -1 and c =-1

then;

y = \frac{-(-1)\pm \sqrt{(-1)^2-4(2)(-1)}}{2(2)}

Simplify:

y = \frac{ 1 \pm \sqrt{1+8}}{4}

or

y = \frac{ 1 \pm \sqrt{9}}{4}

y = \frac{ 1 \pm 3}{4}

or

y = \frac{1+3}{4} and y = \frac{1 -3}{4}

Simplify:

y = 1 and y = -\frac{1}{2}

Substitute y = cos x we have;

\cos x = 1

⇒x = 0^{\circ}

and

\cos x = -\frac{1}{2}

⇒ x = 120^{\circ} \text{and} x = 240^{\circ}

The solution set:  \{0^{\circ}, 120^{\circ} , 240^{\circ}\}

Therefore, the solution for the given equation  2\cos^2x -\cos x -1 =0 is, 0^{\circ}





8 0
4 years ago
Read 2 more answers
What is x?<br><br> 3-2x=21<br><br> Show the steps?
JulsSmile [24]

Answer:

x = -9

Step-by-step explanation:

3-2x=21

-3       -3

-2x=18

/-2   /-2

x=-9

3 0
4 years ago
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