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Nesterboy [21]
2 years ago
12

Question 8: Find the equation of the straight line that:

Mathematics
2 answers:
Scorpion4ik [409]2 years ago
8 0

Answer:

y=4x+6

Step-by-step explanation:

Hi there!

Linear equations are typically organized in slope-intercept form: y=mx+b where m is the slope (also called the gradient) and b is the y-intercept (the value of y when x is 0)

<u>1) Plug the gradient into the equation (b)</u>

y=mx+b

We're given that the gradient of the line is 4. Plug this into y=mx+b as m:

y=4x+b

<u>2) Determine the y-intercept (b)</u>

y=4x+b

Plug in the given point (1,10) as (x,y) and solve for b

10=4(1)+b\\10=4+b

Subtract 4 from both sides to isolate b

10-4=4+b-4\\6=b

Therefore, the y-intercept of the line is 6. Plug this back into y=4x+b as b:

y=4x+6

I hope this helps!

svet-max [94.6K]2 years ago
6 0

answer = y = 4x + 6

y = mx + b

gradient = slope = m = 4

(1,10) = (x,y)

plug in the values

10 = 4 (1) + b

10 = 4 + b

b = 6

y = 4x + 6

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Answer:

-4/3

Step-by-step explanation:

the formula for slope of a line is Y2-Y1

X2-X1

taking any two points from the table ,

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3 years ago
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MrRa [10]

Answer:

y = - 3x + 5

Step-by-step explanation:

The equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

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m = (y₂ - y₁ ) / (x₂ - x₁  )

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