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Fiesta28 [93]
3 years ago
7

If there is 1/6 of a cake and Mitchell only wants 3/12 of it. how much of the cake does he want?

Mathematics
2 answers:
kherson [118]3 years ago
8 0

he wants 1/24 of the cake

Marta_Voda [28]3 years ago
8 0

Answer:

Mitchell wants \frac{1}{24} of the cake.

Step-by-step explanation:

There is \frac{1}{6} of cake and Mitchell wants \frac{3}{12} of the cake.

<em>Observation: The word "of" means "multiply"</em>

This means, \frac{3}{12} .\frac{1}{6}

Then \frac{3}{12} .\frac{1}{6}=\frac{3}{72}

We can simplify: \frac{3}{72}=\frac{3.1}{3.24}=\frac{3}{3}.\frac{1}{24}=\frac{1}{24}

Then Mitchell wants \frac{1}{24} of the cake.

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A printer will produce Katie wedding invitations for $210. The price to produce 120 invitations is $290. The printer uses a line
VMariaS [17]

Thank you for asking this question. Here is your answer:


M = y2 - y1/x2 - X1 = M


= 290 - 210/120 - 80  



M = 80/40


M = 2


Now we will consider y intercept


y = mx + b  


210 = 2(80) + b  


210 = 160 + b  


b = 210 - 160


= 50


Now we will combine everything in order to get the answer.


y = 2x + 50


y = 2(60) + 50  


y = 120 + 50  


y = 170


So the final answer for this question is $170.


If there is any confusion please leave a comment below.


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