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Nitella [24]
3 years ago
14

Cassidy wrote the linear equation y=5x+4 Then, she wrote the equation of the line that is parallel to y=5x+4 and that passes thr

ough (8,–2). If her new equation is in the form y=5x+b what is the value of b? please helpppp
Mathematics
1 answer:
Daniel [21]3 years ago
3 0
Well, again <span>y=5x+4  is in slope-intercept form, therefore    </span>\bf y=\stackrel{slope}{5}x+4.

so then, a parallel line to a line with that equation, will also have the same slope, therefore, what's the equation of a line whose slope is 5 and goes through 8, -2?

\bf \begin{array}{lllll}&#10;&x_1&y_1\\&#10;%   (a,b)&#10;&({{8}}\quad ,&{{ -2}})&#10;\end{array}&#10;\\\\\\&#10;% slope  = m&#10;slope = {{ m}}= \cfrac{rise}{run} \implies 5&#10;\\\\\\&#10;% point-slope intercept&#10;\stackrel{\textit{point-slope form}}{y-{{ y_1}}={{ m}}(x-{{ x_1}})}\implies y-(-2)=5(x-8)\implies y+2=5x-40&#10;\\\\\\&#10;y=5x-40-2\implies y=5x-42
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