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4 years ago

14

Cassidy wrote the linear equation y=5x+4 Then, she wrote the equation of the line that is parallel to y=5x+4 and that passes thr

ough (8,–2). If her new equation is in the form y=5x+b what is the value of b? please helpppp

1 answer:

Daniel [21]4 years ago

3 0

Well, again <span>y=5x+4 is in slope-intercept form, therefore </span> $\bf y=\stackrel{slope}{5}x+4$ .

so then, a parallel line to a line with that equation, will also have the same slope, therefore, what's the equation of a line whose slope is 5 and goes through 8, -2?

$\bf \begin{array}{lllll}
&x_1&y_1\\
% (a,b)
&({{8}}\quad ,&{{ -2}})
\end{array}
\\\\\\
% slope = m
slope = {{ m}}= \cfrac{rise}{run} \implies 5
\\\\\\
% point-slope intercept
\stackrel{\textit{point-slope form}}{y-{{ y_1}}={{ m}}(x-{{ x_1}})}\implies y-(-2)=5(x-8)\implies y+2=5x-40
\\\\\\
y=5x-40-2\implies y=5x-42$

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frutty [35]

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3 years ago

Each sequence below gives an explicit formula. Write the first five terms of each sequence. Then, write a recursive

Bas_tet [7]

Answer:

The first five values are 12, 14, 16, 18 and 20

The recursive formula is as follow

$\left \{ {{a_{1} =12} \atop {a_{n} =a_{n-1} } + 2} \right.$

Step-by-step explanation:

Since we need to find the first 5 values we start with n = 1 to n = 5. Note that we don't start from n = 0 as the question states that n ≥ 1.

For the first 5 values we just replace the value of n with 1, 2, 3, 4 and 5 and calculate the answer

$a_{1} = 2(1) + 10 = 12\\ a_{2} = 2(2) + 10 = 14\\ a_{3} = 2(3) + 10 = 16\\ a_{4} = 2(4) + 10 = 18\\ a_{5} = 2(5) + 10 = 20$

The first five values are 12, 14, 16, 18 and 20

A recursive formula is one that

a) Mentions the initial term

b) provides a formula connecting the previous term to the existing term.

Since we know the first term is 12, i.e $a_{1} = 12$ and we know that the difference between consecutive terms is 2 we can conclude that the recursive formula is made up of the following two formulas

$a_{1} = 12$

$a_{n} = a_{n-1} + 2$

The over all formula is as follow

$\left \{ {{a_{1} =12} \atop {a_{n} =a_{n-1} } + 2} \right.$

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3 years ago

The numbers on two consecutively numbered gym lockers have a sum of 137. what are the locker numbers ?

nika2105 [10]

Answer:

The two locker numbers are 68 & 69.

Step-by-step explanation:

Let one locker number be x then other will be , then other will be x+1.

We are given that sum is 137.

x+x+1=137

2x+1=137

2x=136

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3 years ago

1. Suppose D has a coordinate of 11 and DE = 5. What are the possible<br> midpoints of DE?

Rasek [7]

Answer:

The possible midpoints are (5.5,8) and (5.5,3)

Step-by-step explanation:

Given

$D = 11$

$DE = 5$

Required

Determine the midpoint of DE

First, we need to determine the coordinates of E

If E is to the right of DE;

$E - D = 5$

$E - 11 = 5$

$E = 11 + 5$

$E = 16$

Hence, the coordinate is (11,16)

$Midpoint = \frac{1}{2} * (11,16)$

$Midpoint = (5.5,8)$

Else:

$D - E = 5$

$11 - E = 5$

$E = 11 - 5$

$E = 6$

Hence, the coordinate is (11,6)

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3 years ago

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bearhunter [10]

Answer:

isnt that

Step-by-step explanation:

the answer is 36

my theory: 9*4=36/4=<em><u>9</u></em>

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3 years ago

Read 2 more answers