Cassidy wrote the linear equation y=5x+4 Then, she wrote the equation of the line that is parallel to y=5x+4 and that passes thr

Question

Nitella [24]

3 years ago

14

Cassidy wrote the linear equation y=5x+4 Then, she wrote the equation of the line that is parallel to y=5x+4 and that passes thr

ough (8,–2). If her new equation is in the form y=5x+b what is the value of b? please helpppp

Mathematics

1 answer:

Daniel [21] · Answer 1 · 2021-12-15T13:37:43+03:00

Daniel [21]3 years ago

3 0

Well, again <span>y=5x+4 is in slope-intercept form, therefore </span> $\bf y=\stackrel{slope}{5}x+4$ .

so then, a parallel line to a line with that equation, will also have the same slope, therefore, what's the equation of a line whose slope is 5 and goes through 8, -2?

$\bf \begin{array}{lllll}
&x_1&y_1\\
% (a,b)
&({{8}}\quad ,&{{ -2}})
\end{array}
\\\\\\
% slope = m
slope = {{ m}}= \cfrac{rise}{run} \implies 5
\\\\\\
% point-slope intercept
\stackrel{\textit{point-slope form}}{y-{{ y_1}}={{ m}}(x-{{ x_1}})}\implies y-(-2)=5(x-8)\implies y+2=5x-40
\\\\\\
y=5x-40-2\implies y=5x-42$