Answer:
(A) Payback period for the machine= 3.5 years
(B) Simple rate of return for the machine= 87.5%
Explanation:
Alesu corporation is considering purchasing a machine that would cost $283,850
The useful life is 5 years
The machine would reduce cash operating costs by $81,100 per year
The salvage value is $107,100
(A) The payback period for the machine can be calculated as follows
= cost/amount of cash flow
= 283,850/81,100
= 3.5 years
(B) The simple rate of return for the machine can be calculated as follows
First we calculate the depreciation expense
= 283,850-107,100/5
= 176,750/5
= 35,350
Annual incremental income= cost savings -depreciation expenses
= 283,850-35,350
= 248,500
Simple rate of return = annual incremental income/cost × 100
= 248,500/283,850 × 100
= 0.875 × 100
= 87.5%
The sales era was 1920s-1940s
A.
Low credit scores usually indicate irresponsible spending behaviors.
e. Corporate dividends represent aftertax income from the corporation which becomes taxable income for the recipient.
More about dividends:
Dividend refers to a distribution of a corporation's profits to its shareholders and to use the term distribution to refer to other payments to shareholders, such as payments made when the corporation is liquidated.
Types:
- Cash the most typical and probably the most appreciated type of dividend is cash, which is typically distributed in the form of a check payable to the shareholder.
- Property dividends are the least frequent dividends declared, making them less appealing to shareholders who may not want to receive a variety of the company's goods.
- Share dividends are payments made on the corporation's shares to shareholders in proportion to their individual ownership stakes in the corporation.
Learn more about dividends here:
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Answer:
$2,740,251.24
Explanation:
Applying power sizing technique or an exponential model to determine the cost of new boiler.
This model identify the cost variation along with change in capacity or power of the equipment.
![\frac{C_{A} }{C_{B} } =(\frac{S_{A}}{S_{B}})^{x}](https://tex.z-dn.net/?f=%5Cfrac%7BC_%7BA%7D%20%7D%7BC_%7BB%7D%20%7D%20%3D%28%5Cfrac%7BS_%7BA%7D%7D%7BS_%7BB%7D%7D%29%5E%7Bx%7D)
Where,
Cb = Cost of new plant
Sa = capacity of new plant
Sb = capacity of old plant
x = cost capacity factor
Therefore,
![\frac{C_{A}}{2,000,000} =(\frac{400,000}{250,000})^{0.67}](https://tex.z-dn.net/?f=%5Cfrac%7BC_%7BA%7D%7D%7B2%2C000%2C000%7D%20%3D%28%5Cfrac%7B400%2C000%7D%7B250%2C000%7D%29%5E%7B0.67%7D)
![C_{A}=2,000,000\times\frac{400,000}{250,000}](https://tex.z-dn.net/?f=C_%7BA%7D%3D2%2C000%2C000%5Ctimes%5Cfrac%7B400%2C000%7D%7B250%2C000%7D)
= 2,000,000 × 1.3701
= $2,740,251.24