Triangle MNP will be dilated according to the rule

Mathematics

2 answers:

astra-53 [7]3 years ago

5 0

Answer:

Option B is correct.

N' =(-2, 6) will be the coordinates of vertex N' of the image.

Step-by-step explanation:

Triangle MNP will be dilated according to the rule (x,y), where point P is the center of dilation.

Given the coordinate N = (0, 2)

The rule of dilation with scale factor k =2 and point P is the center of dilation is given by:

$(x, y) \rightarrow (2x -2 , 2y +2)$

then;

$N(0, 2) \rightarrow N'(2(0) -2 , 2(2) +2) = N'(-2, 6)$

Therefore, the coordinate of vertex N' of the image is, (-2, 6)

finlep [7]3 years ago

5 0

Answer:

The answer is B

Step-by-step explanation:

Ed2020

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$\displaystyle \Large \boldsymbol{} 5\cdot \sqrt{3:2\sqrt{3-\sqrt{2} } } =\\\\\\ 5\cdot \sqrt{\frac{3}{2\sqrt{3-\sqrt{2} } } \cdot \frac{2\sqrt{3+\sqrt{2} } }{2\sqrt{3+\sqrt{2} } } } = \\\\\\5\cdot \sqrt{\frac{6\sqrt{3+\sqrt{2} } }{4\cdot \sqrt{9-2} } } =5\sqrt{\frac{6\sqrt{3+\sqrt{2} } }{2\sqrt{7} } }$

But if the condition would be like this

$\displaystyle \Large \boldsymbol{} 5\cdot \sqrt{3:2\sqrt{3-\boldsymbol2\sqrt{2} } } =\\\\\\5\cdot \sqrt{\frac{3}{2\cdot \sqrt{\underbrace{2+1-2\sqrt{2} \cdot \sqrt{1} }_{(\sqrt{2} -1)^2} } }} =\\\\\\5\cdot \sqrt{\frac{3}{2\cdot (\sqrt{2}-1) } } } = \\\\\\ 5\cdot \sqrt{\frac{3}{2(\sqrt{2}-1 )} \cdot \frac{\sqrt{2} +1}{\sqrt{2}+1 }} =5 \sqrt{\frac{3}{2(2-1)} } =\boxed{5\sqrt{1,5} }$