The Gilbert family bought airline tickets online. Each ticket cost $167. The Web site charged $19 per ticket, as well as a flat
1 answer:
You might be interested in
Part I:
1. If you have to circle each outcome in the table that at least 1 die is a 4, then you have to circle row corresponding to the number 4 and column corresponding to the number 4.
2. If you have to cross out each outcome where the sum of the dice is greater than 5, then you have to cross out all not bold numbers 6, 7, 8, 9, 10, 11 and 12 in the table.
Part II:
Here you can see 36 possible outcomes.
1. The probability that at least 1 die is a 4 is:
- (favorable outcomes are 4+1=5, 4+2=6, 4+3=7, 4+4=8, 4+5=9, 4+6=10, 1+4=5, 2+4=6, 3+4=7, 5+4=9, 6+4=10).
2. The probability that the sum of the dice is greater than 5 is:
3. The probability that at least 1 die is a 4 and that the sum of the dice is greater than 5 is
4. The probability that at least 1 die is a 4 or that the sum of the dice is greater than 5 is:
Answer:
<em>Choose the first alternative</em>
Step-by-step explanation:
<u>Probabilities</u>
The requested probability can be computed as the ratio between the number of ways to choose two sophomores in alternate positions and the total number of possible choices
, i.e.
There are 6 sophomores and 14 freshmen to choose from each separate set. There are 20 students in total
We'll assume the positions of the selections are NOT significative, i.e. student A/student B is the same as student B/student A.
To choose 2 sophomores out of the 6 available, the first position has 6 elements to choose from, the second has now only 5
The total number of possible choices is
The probability is then
Choose the first alternative