Answer:
Given the function: y=f(x) = 3x+2
when x=-2 at the beginning of the interval [-2, 5],
then;
y = 3x+2 begins at
y= 3(-2)+2 = -6+2= -4.
and
when x=5 at the end of the interval [-2, 5],
y = 3x+2 ends up at
y= 3(5)+2 = 15+2= 17.
So,
y has changed -4 to 17, which is a change of 17-(-4)= 17+4 = 21
and x has changed from -2 to 5, which is a change of 5-(-2)=5+2=7
So, the average rate of change of y with respect to x over the interval
[-2, 5] is given by ;
=
Therefore, the average rate of change y with respect to x over the interval is, 3
Step-by-step explanation:
#2 is answer 4, #3 is answer 3, #4 is answer 4. The answer to #5 is 6xy if it is a possibility.
Answer:
Step-by-step explanation:
The vertex form of a quadratic equation <em>y = ax² + bx + c:</em>
<em>y = a(x - h)² + k</em>
(h, k) - coordinates of a vertex
We have the equation <em>y = x² - 6x + 6</em>.
Convert to the vertex form:
