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2 years ago

I don’t know the answer

Mathematics

2 answers:

julia-pushkina [17]2 years ago

8 0

12.09 ...........................

Sunny_sXe [5.5K]2 years ago

5 0

Answer:

AC ≈ 12.9 cm

Step-by-step explanation:

Using the ratio

sin40° = $\frac{b}{20}$

Multiply both sides by 20

20 × sin40° = b, hence

AC = b = 20 × sin40° ≈ 12.9

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If a quadratic equation has a real root, what do you know about the other roots of the equation? Explain.

notsponge [240]

Answer:

A Quadratic Equation can have upto 2 roots maximum. So,if one of the roots is a Real number, there are following two possibilities:

1) The other root is also a real number, but a different number

2) Its a repeated root, so the other root is the same number.

The other root cannot be a complex number as its not possible for one root to be real and other to be complex. Either no root will be complex or both will be complex roots.

Following are 3 possibilities for the roots of a quadratic equation:

2 Real and Distinct roots
2 Real and Equal roots
2 Complex roots

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2 years ago

chris runs 2.3 miles every day of the week, except sunday. on sunday he only runs 2 miles. how many miles will he run in 2 weeks

Ludmilka [50]

Answer:

He will run 31.6 miles in two weeks.

Step-by-step explanation:

6 days a week = 2.3 miles

6 days · 2 weeks = 12 days total running 2.3 miles

1 day a week = 2 miles

1 day · 2 weeks = 2 days total running 2 miles

(12 · 2.3) + (2 · 2)

27.6 + 4

31.6 miles

7 0

3 years ago

Can anyone Help me pleasee ?

3241004551 [841]

Answer:

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Step-by-step explanation:

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2 years ago

If an object is launched at an angle of 28° with an initial velocity of 133 ft./s from a height of 6 feet how many seconds will

Tema [17]

Answer:

Hence after 3.98 sec i.e 4 sec Object will hit the ground .

Step-by-step explanation:

Given:

Height= 6 feet

Angle =28 degrees.

V=133 ft/sec

To Find:

Time in seconds after which it will hit the ground?

Solution:

<em>This problem is related to projectile motion for objec</em>t

First calculate the Range for object and it is given by ,

$R=v^2Sin$ (2Ф)/ $g$

Here R= range g= acceleration due to gravity =9.8 m/sec^2

1m =3.2 feet

So 9.8 m, equals to 9.8 *3.2=31.36 ft

So g=31.36 ft/sec^2. and 2Ф=2(28)=56

$R=133^2*Sin(56)/31.36$

$R=14664.84/31.36$

$R=467.62$ fts

Now using Formula for time and range as

$R=VxT$

Vx is horizontal velocity

$Vx=V*cos$ Ф

$Vx=133*cos$ (28)

$Vx=117.43$ ft/sec

So above equation becomes as ,

$467.62=117.43*T$

$T=467.62/117.43$

$T=3.98 sec$

T is approximately equals to 4 sec.

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3 years ago

Next, you will make a scatterplot. Name a point that will be on your scatterplot and describe what it represents.

klio [65]

The point (12, 190) means that the temperature after 12 hours is 190 degrees Celsius

<h3>How to make a scatter plot?</h3>

To do this, we make use of the following points

(12, 190), (14, 201), (15, 301), (16, 305), (18, 350), (20, 40), (25, 450)

Where x represents the number of hours and y represents temperature

See attachment for the scatter plot.

<h3>The description of a point</h3>

To do this, we make use of the point (12, 190)

This means that the temperature after 12 hours is 190 degrees Celsius