Completely lost. do i have to use the slope intercept equation in anyway?

Please help I would love it if you do (math)

beks73 [17]

This question is basically asking you what number was this originally until we timesed it by 100. For the first column take away two zeros or for answers like 560 and 4830 imagine there is a decimal point at the end and move it two spaces forward so it would now be 5.6 and 48.3

For the second column add two zeros at the end instead.

For the questions at the bottom basically for all the questions except the bottom one how many numbers follow the first number.

For example.

96,629 = 1
100

Because three numbers follow the first 6.

Hope this makes sense because I don’t know if it does.

3 0

3 years ago

For y = 6/x² estimate the value of 6/(4.03)².

Aleks [24]

=ligma baalls so that I can tape this d to your fore head so you can cd’s nuts

6 0

2 years ago

The National Center for Education Statistics surveyed a random sample of 4400 college graduates about the lengths of time requir

Paha777 [63]

Answer:

95% confidence interval for the mean time required to earn a bachelor’s degree by all college students is [5.10 years , 5.20 years].

Step-by-step explanation:

We are given that the National Center for Education Statistics surveyed a random sample of 4400 college graduates about the lengths of time required to earn their bachelor’s degrees. The mean was 5.15 years and the standard deviation was 1.68 years respectively.

Firstly, the pivotal quantity for 95% confidence interval for the population mean is given by;

P.Q. = $\frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } }$ ~ N(0,1)

where, $\bar X$ = sample mean time = 5.15 years

$\sigma$ = sample standard deviation = 1.68 years

n = sample of college graduates = 4400

$\mu$ = population mean time

Here for constructing 95% confidence interval we have used One-sample z test statistics although we are given sample standard deviation because the sample size is very large so at large sample values t distribution also follows normal.

So, 95% confidence interval for the population mean, $\mu$ is ;

P(-1.96 < N(0,1) < 1.96) = 0.95 {As the critical value of z at 2.5%

level of significance are -1.96 & 1.96}

P(-1.96 < $\frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } }$ < 1.96) = 0.95

P( $-1.96 \times {\frac{\sigma}{\sqrt{n} } }$ < ${\bar X-\mu}$ < $1.96 \times {\frac{\sigma}{\sqrt{n} } }$ ) = 0.95

P( $\bar X-1.96 \times {\frac{\sigma}{\sqrt{n} } }$ < $\mu$ < $\bar X+1.96 \times {\frac{\sigma}{\sqrt{n} } }$ ) = 0.95

95% confidence interval for $\mu$ = [ $\bar X-1.96 \times {\frac{\sigma}{\sqrt{n} } }$ , $\bar X+1.96 \times {\frac{\sigma}{\sqrt{n} } }$ ]

= [ $5.15-1.96 \times {\frac{1.68}{\sqrt{4400} } }$ , $5.15+1.96 \times {\frac{1.68}{\sqrt{4400} } }$ ]

= [5.10 , 5.20]

Therefore, 95% confidence interval for the mean time required to earn a bachelor’s degree by all college students is [5.10 years , 5.20 years].

8 0

3 years ago

Help me out !!!!! Please

Stella [2.4K]

4x-t-4 is the final answer.

4 0

3 years ago

When creating vases for the craft fair, Thomas used the proportion 3 pounds of clay is to 8 vases as 9 pounds of clay is to 24 v

spayn [35]

The proportion of clay uses is 3/8 (Three Eighths). That is 3 lbs. of clay to every 8 vases. This is determined by the first given proportion 3 lbs./8 vases and confirmed by the second. To prove that is the case you divide the second ration by the first numerator: 9 divided by 3 = 3 and 24 divided by 3 = 8. So the proportion for 9/24 is still 3/8. This can also be used to increase the number of vases made. For example if 40 vases need to be made: we divide 40 by the numerator 8 = 5. So we need 5 portions of 3 to make 40 vases. 5 times 3 = 15. So the 15 lbs. of clay is needed for 40 vases.

8 0

3 years ago

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