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stiks02 [169]
3 years ago
15

A manufacturer producing a new product, estimates the annual sales to be 9,600 units. Each year, 8% of the units that have been

sold will become inoperative. So, 9,600 units will be in use after 1 year, [9,600 0.92(9,600)] units will be in use after 2 years, and so on. How many units will be in use after n years
Mathematics
1 answer:
Crazy boy [7]3 years ago
4 0

Answer:

After n years, 120,000(1 - 0.92ⁿ) units, will be in use.

Step-by-step explanation:

Given;

estimated annual sales, a = 9600 units

determine common ratio, r;

r = 1 - \frac{8}{100}\\\\r = 0.92

sum of the units in use after n years is calculated by applying sum of nth term;

S_n = \frac{a}{1-r} (1-r^n)

S_n = \frac{9600}{1-0.92} (1-0.92^n)\\\\S_n = \frac{9600}{0.08} (1-0.92^n)\\\\S_n = 120,000(1-0.92^n) \ units

Therefore, after n years, 120,000(1 - 0.92ⁿ) units, will be in use.

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A) 2

Step-by-step explanation:

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3 years ago
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3 years ago
Is each fraction in simples form? Write yes or no 2/4
shusha [124]
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8 0
3 years ago
Read 2 more answers
<img src="https://tex.z-dn.net/?f=3x%20-%202y%20%3D%2043x%20%2B%202y%20%3D%208" id="TexFormula1" title="3x - 2y = 43x + 2y = 8"
den301095 [7]

3x - 2y = 8 +

===》 46x = 16

43x + 2y = 8

x = 16/46

x = 8/23

______________________________

3x - 2y = 8

3(8/23) - 2y = 8

24/23 - 2y = 8

2y = 24/23 - 8

y = 12/23 - 4

y = 12/23 - 92/23

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