The gas phase decomposition of dimethyl ether at 500 °C CH3OCH3(g) → CH4 (g) + H2 (g) + CO (g) is first order in CH3OCH3 with a
rate constant of 4.00×10-4 s-1 How much time in seconds is required for 85.2% of the CH3OCH3 initially present in a reaction flask to be converted to product at this temperature? (enter a numerical value, don't worry about the units, put exponents as e#. For example, 4.00×10-4 would be 4.00e-4)
1 answer:
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Answer:
<h3>The answer is 1.5 g/mL</h3>Explanation:
The density of a substance can be found by using the formula
From the question we have
We have the final answer as
<h3>1.5 g/mL</h3>Hope this helps you